基于python中的时间戳排序字典 [英] Sort dictionaries based on timestamp in python

问题描述

这是我的列表，

[{u'lang': u'en', u'createdAt': 1326158349, u'canonicalUrl': u'https://foursquare.com/item/4f0b920de4b0c4aaa8bc78ec', u'text': u'one of the great restaurant in new haven , excellent food and service', u'user': {u'lastName': u'S.', u'gender': u'male', u'id': u'19483764', u'firstName': u'Ram', u'photo': {u'prefix': u'https://irs0.4sqi.net/img/user/', u'suffix': u'/blank_boy.png'}}, u'todo': {u'count': 0}, u'id': u'4f0b920de4b0c4aaa8bc78ec', u'logView': True, u'likes': {u'count': 2, u'groups': [{u'count': 2, u'items': [], u'type': u'others'}], u'summary': u'2 likes'}}, {u'lang': u'en', u'createdAt': 1305643797, u'canonicalUrl': u'https://foursquare.com/item/4dd28b15227159fef24d285a', u'url': u'http://www.goscoville.com', u'text': u'buffet quality is alright, and it is cheap', u'user': {u'lastName': u'E.', u'gender': u'male', u'id': u'2617284', u'firstName': u'Perry', u'photo': {u'prefix': u'https://irs1.4sqi.net/img/user/', u'suffix': u'/1OWJL2FYLHWGJGZS.jpg'}}, u'todo': {u'count': 0}, u'id': u'4dd28b15227159fef24d285a', u'logView': True, u'likes': {u'count': 1, u'groups': [{u'count': 1, u'items': [], u'type': u'others'}], u'summary': u'1 like'}}, {u'lang': u'en', u'createdAt': 1352054660, u'canonicalUrl': u'https://foursquare.com/item/5096b784e4b079e230cea793', u'text': u"They're not too talented with meat dishes, so come here for the excellent vegetarian meals, which is the majority of the menu.", u'user': {u'lastName': u'P.', u'gender': u'male', u'id': u'5505251', u'firstName': u'Alex', u'photo': {u'prefix': u'https://irs0.4sqi.net/img/user/', u'suffix': u'/5505251-KAWIX0MMDUPYIS2C.jpg'}}, u'todo': {u'count': 0}, u'id': u'5096b784e4b079e230cea793', u'logView': True, u'likes': {u'count': 0, u'groups': []}}, {u'lang': u'en', u'createdAt': 1337213142, u'canonicalUrl': u'https://foursquare.com/item/4fb440d6e4b002d950289ae6', u'text': u'Stay away from the long haired creepy waiter! Also the shrimp with garlic sauce is reportedly delightful.', u'user': {u'lastName': u'G.', u'gender': u'female', u'id': u'28141671', u'firstName': u'Molly', u'photo': {u'prefix': u'https://irs2.4sqi.net/img/user/', u'suffix': u'/blank_girl.png'}}, u'todo': {u'count': 0}, u'id': u'4fb440d6e4b002d950289ae6', u'logView': True, u'likes': {u'count': 0, u'groups': []}}, {u'lang': u'en', u'createdAt': 1329162806, u'canonicalUrl': u'https://foursquare.com/item/4f396a36e4b0653d4cc83fad', u'text': u'Try the Pho with Chicken (via @Foodspotting)', u'user': {u'lastName': u'c.', u'gender': u'male', u'id': u'3893645', u'firstName': u'louis', u'photo': {u'prefix': u'https://irs1.4sqi.net/img/user/', u'suffix': u'/RWFVP1ETQT0KWQRE.jpg'}}, u'todo': {u'count': 1}, u'id': u'4f396a36e4b0653d4cc83fad', u'logView': True, u'likes': {u'count': 0, u'groups': []}}]

如何根据 timestamp对其元素进行排序？ [createdAt key of dict] ？

推荐答案

使用 list.sort （inplace sorting）或 （返回新的排序列表）并通过键功能。键功能的返回值用于比较：

Use list.sort (inplace sorting) or sorted (returns new sorted list) and pass key function. The return value of the key function is used for comparison:

lst.sort(key=lambda d: d['createdAt'])

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