基于时间戳的grep文件 [英] grep files based on time stamp

问题描述

这应该是非常简单的，但我没有搞清楚。我在Linux下有一个超过4GB的大代码库。构建期间会生成一些头文件和xml文件（使用gnu make）。

我想在时间实例后最后修改的头文件中搜索一个关键字（它是我的开始编译时间）和类似的xml文件，但单独的grep查询。

如果我在所有可能的头文件或xml文件上运行它，它会花费很多时间。只有那些是自动生成的。进一步的搜索必须是递归的，因为有很多的目录和子目录。

解决方案

在当前目录及其子目录中递归地添加比 some_file 更新的所有文件中的$ c>'pattern'：

  find -newer some_file -type f -exec grep'pattern'{} + 
  

您可以直接在 date -d 格式中指定时间戳，并使用其他 find 测试，例如 -name ， -mmin 。

如果 find 太慢，文件列表也可能由您的构建系统生成。

更具体工具，如 ack ， etags ，可以使用 GCCSense 来代替 grep 。

This should be pretty simple, but I am not figuring it out. I have a large code base more than 4GB under Linux. A few header files and xml files are generated during build (using gnu make). If it matters the header files are generated based on xml files.

I want to search for a keyword in header file that was last modified after a time instance ( Its my start compile time), and similarly xml files, but separate grep queries.

If I run it on all possible header or xml files, it take a lot of time. Only those that were auto generated. Further the search has to be recursive, since there are a lot of directories and sub-directories.

解决方案

To find 'pattern' in all files newer than some_file in the current directory and its sub-directories recursively:

find -newer some_file -type f -exec grep 'pattern' {} +

You could specify the timestamp directly in date -d format and use other find tests e.g., -name, -mmin.

The file list could also be generate by your build system if find is too slow.

More specific tools such as ack, etags, GCCSense might be used instead of grep.

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