Django获取显示名称的选择 [英] Django get display name choices
本文介绍了Django获取显示名称的选择的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在寻找解决问题的方法。
I'm trying to find a solution to my problem.
models.py
models.py
class Article(models.Model):
title = models.CharField(max_length=100)
slug = models.SlugField()
description = models.TextField()
def archive_quality(self):
return self.archive_set.order_by('-quality').distinct().values_list('quality', flat=True)
class Archive(models.Model):
CHOICES_QUALITY = (
('1', 'HD YB'),
('2', 'HD BJ'),
('3', 'HD POQD'),
('4', 'HD ANBC'),
)
article = models.ForeignKey(Article)
quality = models.CharField(max_length=100, choices=CHOICES_QUALITY)
arhives.html
arhives.html
{% for article in articles %}
{{ article }}
{% for quality in article.archive_quality %}
{{ quality.get_quality_display }}#This is not working
{% endfor %}
{% endfor %}
更新
函数archive_quality是很重要的,因为它可以防止模板对象中的重现。
Update The function archive_quality is important, because it prevents recurrence in the template objects.
Example:
article:
My article one
Archive:
quality: 1111222333 >> without the function
quality: 123 >> with function
推荐答案
选项#1: strong>
Option #1:
models.py
models.py
CHOICES_QUALITY = (
('1', 'HD YB'),
('2', 'HD BJ'),
('3', 'HD POQD'),
('4', 'HD ANBC'),
)
class Article(models.Model):
title = models.CharField(max_length=100)
slug = models.SlugField()
description = models.TextField()
def archive_quality(self):
quality = self.archive_set.order_by('-quality').distinct().values_list(
'quality', flat=True)
lists = []
for q in quality:
for choice in CHOICES_QUALITY:
if choice[0] == q:
lists.append({'quality': choice[1]})
return lists
class Archive(models.Model):
article = models.ForeignKey(Article)
quality = models.CharField(max_length=100, choices=CHOICES_QUALITY)
模板
{% for article in articles %}
{% for item in article.archive_quality %}
{{ item.quality }},
{% endfor %}
{% endfor %}
选项#2:
archive_tag.py
archive_tag.py
from django import template
from app_name.models import CHOICES_QUALITY
register = template.Library()
@register.filter
def quality(q):
for choice in CHOICES_QUALITY:
if choice[0] == q:
return choice[1]
return ''
模板
{% load archive_tag %}
{% for article in articles %}
{% for item in article.archive_quality %}
{{ item|quality }},
{% endfor %}
{% endfor %}
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