如何在elisp中传递一个参数作为参数？ [英] How do I pass a function as a parameter to in elisp?

问题描述

我试图在elisp中传递一个方法，然后
使该方法执行。这是一个例子：

I'm trying to pass one method to another in elisp, and then have that method execute it. Here is an example:

(defun t1 ()
  "t1")

(defun t2 ()
  "t1")

(defun call-t (t)
  ; how do I execute "t"?
  (t))

; How do I pass in method reference?
(call-t 't1)

推荐答案

首先，我不确定命名您的函数 t 正在帮助，因为't'被用作真值。

First, I'm not sure that naming your function t is helping as 't' is used as the truth value in lisp.

说，以下代码适用于我：

That said, the following code works for me:

(defun test-func-1 ()  "test-func-1"
   (interactive "*")
   (insert-string "testing callers"))

(defun func-caller (callee)
  "Execute callee"
  (funcall callee))

(func-caller 'test-func-1)

请注意使用'funcall'，触发实际的函数调用。

Please note the use of 'funcall', which triggers the actual function call.

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