发送电子邮件，返回路径不起作用 [英] Sending Email with return-path not functioning

问题描述

我正在使用 System.Net.Mail 电子邮件。在代码中，我设置电子邮件的返回路径如下：

I am using System.Net.Mail email. in the code i am setting the return-path of email as follow:

string sReturnPath = ConfigurationManager.AppSettings["ReturnPath"].ToString();
if (sReturnPath.Length > 0) {
    msg.Headers.Add("Return-Path", sReturnPath);
}

如果交货失败，它应该返回返回路径， t，即使我可以看到电子邮件的返回路径的标题来自我指定的配置文件。

If the delivery has failed it should go to return-path but it doesn't, even though I can see the header of email's return-path being from config file that I specified. The email gets returned to sender.

推荐答案

你使用的方法略为错误。简单邮件传输协议（ RFC 2821 ）说：

You're using a slightly wrong approach. Simple Mail Transfer Protocol (RFC 2821) says:

消息始发的SMTP系统不应发送一条消息，其中

已经包含一个返回路径头。执行

中继功能的SMTP服务器不得检查消息数据，特别是不能

，以确定是否存在返回路径头。

A message-originating SMTP system SHOULD NOT send a message that
already contains a Return-path header. SMTP servers performing a
relay function MUST NOT inspect the message data, and especially not
to the extent needed to determine if Return-path headers are present.

如果您希望将邮件返回到 From指定的地址以外的地址：字段，则应在SMTP消息信封中设置地址，而不是在消息头中设置。您可以通过设置发件人属性来实现此目的：

If you want your message to be returned to the address other than the one specified in the From: field, then the address should be set in the SMTP message envelope rather than in the message header. You can achieve this by setting the Sender property:

MailMessage msg = new MailMessage();
msg.Sender = new MailAddress("[e-mail]", "Sam1");

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