检查Python中的价值和键 [英] Checking values and keys in Python

问题描述

如果我有这样的词典：

dict = {'a': ['Menny','Adam'], 'b': ['Steff','Bentz', 'Arik'], 'c': ['Menny','Stephonich', 'Marry', 'Kenny', 'Mike', 'Pring']

等等。

如果我要检查，如果有一些值是在它们的键2列出的常见的。我该怎么办？

If I want to check if there's some values that are common between 2 lists in their keys. what should I do?

例如， 在a和c有Menny......

For example, in a and c there's "Menny"...

推荐答案

我要建一个逆指数：

from collections import defaultdict

reverse = defaultdict(set)

for key, values in dct.items():
    for value in values:
        reverse[value].add(key)

现在，你可以发现，在关键点之间共享的任何值：

Now you can find any value that is shared between keys:

for value, keys in reverse.items():
    if len(keys) > 1:
        print(value, keys)

演示：

>>> from collections import defaultdict
>>> dct = {'a': ['Menny','Adam'], 'b': ['Steff','Bentz', 'Arik'], 'c': ['Menny','Stephonich', 'Marry', 'Kenny', 'Mike', 'Pring']}
>>> reverse = defaultdict(set)
>>> for key, values in dct.items():
...     for value in values:
...         reverse[value].add(key)
... 
>>> for value, keys in reverse.items():
...     if len(keys) > 1:
...         print(value, keys)
... 
Menny {'c', 'a'}

如果你想测试两个键，使用方法：

If you want to test two keys, use:

def check_keys(dct, key1, key2):
    return not set(dct[key1]).isdisjoint(dct[key2])

演示：

>>> check_keys(dct, 'a', 'c')
True
>>> check_keys(dct, 'a', 'b')
False

，或返回的共同价值观：

or, returning the common values:

def values_intersection(dct, key1, key2):
    return set(dct[key1]).intersection(dct[key2])

演示：

>>> values_intersection(dct, 'a', 'c')
{'Menny'}
>>> values_intersection(dct, 'a', 'b')
set()

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