将Excel列转换为行 [英] Transpose Excel column to rows
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问题描述
我已经写了下面的代码,但是没有按预期的方式工作。它删除比预期更多的行。代码有什么问题?
Sub Trans3()
Dim rng As Range,rng2 As Range
Dim I As Long
Dim J As Integer,Z As Integer,Q As Integer,T As Integer
设置rng = Range(B1)
虽然rng.Value< ;>
对于每个y范围(A1:A10)
I = I + 1
J = I
Z = 1
虽然单元格(J + 1,1).Value =单元格(J,1).Value
J = J + 1
循环
设置rng2 =范围(B& ;:B& J)
如果我> 1然后
Z = J - I + 1
Else
Z = J
如果
rng2.Resize(Z).Copy
Range(C& I).PasteSpecial Transpose:= True
T = I
Do While J> 1
Q = T + 1
行(Q).EntireRow.Delete
J = J - 1
循环
下一个y
Wend
End Sub
解决方案
所以我做了一点重构。
请参阅代码中的附注。
Sub FOOO()
Dim inArr()As Variant
Dim outArr()As Variant
Dim ws As Worksheet
Dim cntrw As Long
Dim cntclm As Long
Dim i As Long
Dim j As Long
Dim k As Long
Dim rng As Range
设置ws = ActiveSheet
用ws
设置rng = .Range(A1,.Cells(.Rows.Count,A)。End(xlUp))
'找到最大数字列这将需要在输出
cntclm = ws.Evaluate(MAX(COUNTIF(& rng.Address&,& rng.Address&)))+ 1
'找到输出中需要的行数。
cntrw = ws.Evaluate(SUM(1 / COUNTIF(& rng.Address&,& rng.Address&)))
'将现有数据放入一个数组
inArr = rng.Resize(,2).Value
'将大小输出数组调整到所需的区域
ReDim outArr(1 To cntrw,1 To cntclm)
'将第一个值放在输出的第一个位置
outArr(1,1)= inArr(1,1)
outArr(1,2)= inArr(1,2)
'这些是计数器来跟踪数据应该去哪个时隙。
j = 3
k = 1
'循环通过现有数据行
对于i = 2 To UBound(inArr,1)
'测试A中的数据是否改变与否
如果inArr(i,1)= inArr(i - 1,1)然后
'如果没有将值放在下一个插槽中的B中,并迭代到下一列
outArr(k ,j)= inArr(i,2)
j = j + 1
Else
'如果更改在outarr中开始一个新行并填写前两个插槽
k = k + 1
j = 3
outArr(k,1)= inArr(i,1)
outArr(k,2)= inArr(i,2)
End If
Next i
'删除旧数据
.Range(A:B)。清除
'将新数据放在其位置。
.Range(A1)。调整大小(UBound(outArr,1),UBound(outArr,2))Value = outArr
End with
End Sub
这样做需要将数据排在A列。
I have an Excel sheet that looks like the first picture and I want to convert it to the second picture:
I have written the following code but it does not work as expected. It deletes more rows than expected. What's wrong with the code?
Sub Trans3()
Dim rng As Range, rng2 As Range
Dim I As Long
Dim J As Integer, Z As Integer, Q As Integer, T As Integer
Set rng = Range("B1")
While rng.Value <> ""
For Each y In Range("A1:A10")
I = I + 1
J = I
Z = 1
Do While Cells(J + 1, 1).Value = Cells(J, 1).Value
J = J + 1
Loop
Set rng2 = Range("B" & I & ":B" & J)
If I > 1 Then
Z = J - I + 1
Else
Z = J
End If
rng2.Resize(Z).Copy
Range("C" & I).PasteSpecial Transpose:=True
T = I
Do While J > 1
Q = T + 1
Rows(Q).EntireRow.Delete
J = J - 1
Loop
Next y
Wend
End Sub
解决方案
So I did a little refactoring. I moved everything into arrays to speed it up.
See notes in code for reference.
Sub FOOO()
Dim inArr() As Variant
Dim outArr() As Variant
Dim ws As Worksheet
Dim cntrw As Long
Dim cntclm As Long
Dim i As Long
Dim j As Long
Dim k As Long
Dim rng As Range
Set ws = ActiveSheet
With ws
Set rng = .Range("A1", .Cells(.Rows.Count, "A").End(xlUp))
'find the max number column that will be needed in the output
cntclm = ws.Evaluate("MAX(COUNTIF(" & rng.Address & "," & rng.Address & "))") + 1
'find the number of rows that will be needed in the output.
cntrw = ws.Evaluate("SUM(1/COUNTIF(" & rng.Address & "," & rng.Address & "))")
'put the existing data into an an array
inArr = rng.Resize(, 2).Value
'resize output array to the extents needed
ReDim outArr(1 To cntrw, 1 To cntclm)
'put the first value in the first spot in the output
outArr(1, 1) = inArr(1, 1)
outArr(1, 2) = inArr(1, 2)
'these are counters to keep track of which slot the data should go.
j = 3
k = 1
'loop through the existing data rows
For i = 2 To UBound(inArr, 1)
'test whether the data in A has changed or not.
If inArr(i, 1) = inArr(i - 1, 1) Then
'if not put the value in B in the next slot and iterate to the next column
outArr(k, j) = inArr(i, 2)
j = j + 1
Else
'if change start a new line in the outarr and fill the first two slots
k = k + 1
j = 3
outArr(k, 1) = inArr(i, 1)
outArr(k, 2) = inArr(i, 2)
End If
Next i
'remove old data
.Range("A:B").Clear
'place new data in its place.
.Range("A1").Resize(UBound(outArr, 1), UBound(outArr, 2)).Value = outArr
End With
End Sub
This does require that the data be sorted on column A.
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