grep没有显示路径/文件:行 [英] grep without showing path/file:line
问题描述
在这种情况下,我想查看当前目录中的所有.bar文件,搜索术语FOO
find。 -name'* .bar'-exec grep -Hn FOO {} \;
不需要 find
。如果你只是在一个特定的目录下寻找一个模式,这应该就足够了:
grep -hn FOO / your / path / * .bar
其中 -h
是参数隐藏文件名,从 man grep
:
h,--no-filename
禁止输出文件名的前缀。这是默认的
,当只有一个文件(或只有标准输入)要搜索。
请注意,我们使用
-H,--with-filename
打印每个比赛的文件名称。这是
多于一个文件进行搜索时的默认值。
How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.
In this case I want to look in all .bar files in the current directory, searching for the term FOO
find . -name '*.bar' -exec grep -Hn FOO {} \;
No need to find
. If you are just looking for a pattern within a specific directory, this should suffice:
grep -hn FOO /your/path/*.bar
Where -h
is the parameter to hide the filename, as from man grep
:
-h, --no-filename
Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.
Note that you we using
-H, --with-filename
Print the file name for each match. This is the default when there is more than one file to search.
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