将数组传递给着色器 [英] Pass array to shader
问题描述
我创建了我的数组this.kernel:它有48个元素,我想把它传递给我的片段着色器。
当我打电话的时候
gl.uniform3fv(gl.getUniformLocation this.program,kernel),16,this.kernel);
在我的着色器中定义了内核:
uniform vec3 kernel [16];
我得到一个没有足够参数的错误。
我已经查找了规范等,但没有找到我的问题-.-
void glUniform3fv(GLint位置,GLsizei计数,const GLfloat *值);
感谢您的帮助
€:转换this.kernel为float32array,但我仍然有这个错误。
2:Chrome中的错误:没有足够的参数
$ b $在Firefox中的b
:NS_ERROR_XPC_BAD_CONVERT_JS:无法转换JavaScript参数
this.kernel
需要是长度为48(= 3 * 16)的Float32Array。你不能使用vec3s数组。 另外,WebGL中不使用计数。该功能(来自 WebGL规范)
void uniform3fv(WebGLUniformLocation?location,Float32Array v);
示例用法:
gl.uniform3fv(gl.getUniformLocation(shaderProgram,colors),new Float32Array([0,1,2,3,4,5]));
查看完整的示例:
http://jsfiddle.net/mortennobel/URvtx/
I create my array this.kernel: it hast 48 elements and I want to pass it to my fragment shader.
When i call
gl.uniform3fv(gl.getUniformLocation(this.program, "kernel"), 16, this.kernel);
kernel is defined in my shader:
uniform vec3 kernel[16];
I get an error for not enough arguments. I already looked up the specification etc, but don't find my problem -.-
void glUniform3fv( GLint location, GLsizei count, const GLfloat * value);
Thanks for help
€: I converted this.kernel to a float32array but I still have this error.
€2: error in Chrome: not enough arguments
in Firefox: NS_ERROR_XPC_BAD_CONVERT_JS: Could not convert JavaScript argument
Your this.kernel
needs to be a Float32Array of length 48 (=3*16). You cannot use an array of vec3s.
Also the count is not used in WebGL. The function is (from WebGL Specification)
void uniform3fv(WebGLUniformLocation? location, Float32Array v);
Example usage:
gl.uniform3fv(gl.getUniformLocation(shaderProgram, "colors"), new Float32Array([0,1,2,3,4,5]));
See a complete example here: http://jsfiddle.net/mortennobel/URvtx/
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