如何在Rails中呈现不同格式的部分内容？ [英] How do I render a partial of a different format in Rails?

问题描述

我试图生成一个包含一些HTML的JSON响应。因此，我有 /app/views/foo/bar.json.erb ：

  {
 someKey：'some value'，
 someHTML：<％= h render（：partial =>'/ foo / baz'） - ％> 
 
 $ / code $ / pre 
 $ b $ p我希望它呈现 / app / views / foo / _baz.html.erb ，但它只会呈现 /app/views/foo/_baz.json.erb 。传递：format => 'html'没有帮助。
解决方案
建立在罗林内克的回应，我发现最好的解决方案在/app/helpers/application.rb中：
 
 
 
 
 
  def with_format（format，&block）
 old_format = @template_format 
 @template_format = format 
 result = block.call 
 @template_format = old_format 
返回结果
 end 
  
 
 
 
在/app/views/foo/bar.json:
 <％with_format（'html'）do％> 
<％= h render（：partial =>'/ foo / baz'）％> 
<％end％> 
  
另一个解决方案是重新定义 render 接受：format 参数。
 
 
 
我无法得到 render：file 可以和当地人一起工作，而且不需要一些路径。
 
I'm trying to generate a JSON response that includes some HTML.  Thus, I have /app/views/foo/bar.json.erb:
{
  someKey: 'some value',
  someHTML: "<%= h render(:partial => '/foo/baz') -%>"
}
I want it to render /app/views/foo/_baz.html.erb, but it will only render /app/views/foo/_baz.json.erb.  Passing :format => 'html' doesn't help.
解决方案
Building on roninek's response, I've found the best solution to be the following:

in /app/helpers/application.rb:
def with_format(format, &block)
  old_format = @template_format
  @template_format = format
  result = block.call
  @template_format = old_format
  return result
end
In /app/views/foo/bar.json:
<% with_format('html') do %>
  <%= h render(:partial => '/foo/baz') %>
<% end %>
An alternate solution would be to redefine render to accept a :format parameter.

I couldn't get render :file to work with locals and without some path wonkiness.

                        
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