MATLAB：如何将参数传递给函数？ [英] MATLAB: How do I pass a parameter to a function?

问题描述

我有以下功能：

 函数ypdiff = ypdiff（t，y）
 a = 0.01; 
 b = 0.1; 
 ypdiff（1）= -a * y（1）* y（2）; 
 ypdiff（2）= b * y（1）* y（2）-b * y（2）; 
 ypdiff（3）= b * y（2）; 
 ypdiff = [ypdiff（1）ypdiff（2）ypdiff（3）]'; 
  

如果我想解决这个问题，我会按如下方式调用ode45函数：

  [ty] = ode45（@ypdiff，[to tf]，yo）; 
  

但是如果我想将一个参数传递给这个函数，我将如何使用ode45函数？具体来说，我正在尝试以下形式：

pre $函数ypdiff = ypdiff（t，y，u）
a = 0.01;
b = 0.1;
ypdiff（1）= -a * u * y（1）* y（2）;
ypdiff（2）= b * u * y（1）* y（2）-b * y（2）;
ypdiff（3）= b * u * y（2）;
ypdiff = [ypdiff（1）ypdiff（2）ypdiff（3）]';

解决方案

您可以使用 anonymous function 在matlab中（类似于其他语言中的lambda函数） p>

  u = 1.2; 
 [t y] = ode45（@（t，y）ypdiff（t，y，u），[to tf]，yo）; 
  

I have the following function:

function ypdiff = ypdiff(t,y)
    a = 0.01;
    b = 0.1;
    ypdiff(1) = -a*y(1)*y(2);
    ypdiff(2) = b*y(1)*y(2)-b*y(2);
    ypdiff(3) = b*y(2);
    ypdiff = [ypdiff(1) ypdiff(2) ypdiff(3)]';

If I want to solve this, I would call the ode45 function as follows:

[t y] = ode45(@ypdiff, [to tf], yo);

But if I want to pass a parameter to this function, how would I use the ode45 function? Specifically, I am trying for the following formulation:

function ypdiff = ypdiff(t,y,u)
    a = 0.01;
    b = 0.1;
    ypdiff(1) = -a*u*y(1)*y(2);
    ypdiff(2) = b*u*y(1)*y(2)-b*y(2);
    ypdiff(3) = b*u*y(2);
    ypdiff = [ypdiff(1) ypdiff(2) ypdiff(3)]';

解决方案

You can use an anonymous function in matlab (similar to lambda functions in other languages):

u = 1.2;
[t y] = ode45(@(t, y) ypdiff(t, y, u), [to tf], yo);

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