如何使用GCC将源代码行与汇编输出内联? [英] How can I get the source lines inline with the assembly output using GCC?
问题描述
我已经尝试了像<$ c这样的GCC选项。
我想让C源代码行与程序集输出内联,以查看正在生成的代码。 $ c> -S -Wa,-ahlms
(甚至 -Wa, - gstabs $ c $因为我在某处读过它)。
哦!顺便说一句,我在Mac上,所以我没有 objdump
。
(对不起, )
$ b
gcc pc -clisp.c -S -g -fverbose -asm -fnested-functions的输出
.globl _getBool
_getBool:
LFB32:
LM21 :
pushl%ebp#
LCFI30:
movl%esp,%ebp#,
LCFI31:
subl $ 8,%esp#,
LCFI32:
LM22:
movzbl 8(%ebp),%eax#atom.pred,D.4112
movzbl%al,%eax#D.4112,D.4113
andl $ -16,%eax#,D.4114
sarl $ 4,%eax#,D.4115
testl%eax,%eax#D.4115
setne%al#,tmp64
movzbl%al,%eax#tmp64,D.4111
leave
ret
LFE32:
也许调试+后处理步骤?
gcc< source.c> -S -g -fverbose -asm
查找 .file 11。 c
来告诉你文件编号到文件名映射。
然后在 .loc 1 8 0
行之后添加源代码。我不知道如何使用单个shell命令来做到这一点,但一个简短的脚本应该能够做到这一点:
#!/ usr / bin / env python
import re
import sys
filename = sys.argv [1]
f = open(filename)
lines = f.readlines()
f.close()
FILE_RE = re.compile(r\ s + \.file(\ (* .d +)(\ d +))
$(+) b $ b output = []
files = {}
用于行内行:
output.append(行)
mo = FILE_RE.match(行)
如果mo不是None:
files [mo.group(1)] = open(mo.group(2))。readlines()
print mo.group(1),=,mo .group(2)
continue
mo = LOC_RE.match(line)
如果mo不是None:
print mo.group(1),=,mo。 group(2)
source = files [mo.group(1)] [int(mo.group(2)) - 1]
output.append(\ t#+ source)
f = open(文件名+。2,w)
f.writelines(o utput)
f.close()
I'd like to get the C source lines inline with the assembly output to see what code is being generated.
I have tried GCC options like -S
-Wa,-ahlms
(and even -Wa,--gstabs
'cause I read it somewhere).
Oh! BTW, I am on a Mac so I don't have objdump
.
(Sorry this is short, I have to get off the train!)
Output of gcc pc-clisp.c -S -g -fverbose-asm -fnested-functions
.globl _getBool
_getBool:
LFB32:
LM21:
pushl %ebp #
LCFI30:
movl %esp, %ebp #,
LCFI31:
subl $8, %esp #,
LCFI32:
LM22:
movzbl 8(%ebp), %eax # atom.pred, D.4112
movzbl %al, %eax # D.4112, D.4113
andl $-16, %eax #, D.4114
sarl $4, %eax #, D.4115
testl %eax, %eax # D.4115
setne %al #, tmp64
movzbl %al, %eax # tmp64, D.4111
leave
ret
LFE32:
Maybe debug + a post-process step?
gcc <source.c> -S -g -fverbose-asm
Find .file 1 "1.c"
to tell you the file number to file name mapping.
Then add source after the .loc 1 8 0
lines. I'm not sure how to do it with a single shell command, but a short script should be able to do it:
#!/usr/bin/env python
import re
import sys
filename = sys.argv[1]
f = open(filename)
lines = f.readlines()
f.close()
FILE_RE=re.compile(r"\s+\.file (\d+) \"(.*)\"")
LOC_RE =re.compile(r"\s+\.loc (\d+) (\d+)")
output = []
files = {}
for line in lines:
output.append(line)
mo = FILE_RE.match(line)
if mo is not None:
files[mo.group(1)] = open(mo.group(2)).readlines()
print mo.group(1),"=",mo.group(2)
continue
mo = LOC_RE.match(line)
if mo is not None:
print mo.group(1),"=",mo.group(2)
source = files[mo.group(1)][int(mo.group(2))-1]
output.append("\t#"+source)
f = open(filename+".2","w")
f.writelines(output)
f.close()
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