无法使用通配符泛型为Java集合添加值 [英] Can't add value to the Java collection with wildcard generic type
问题描述
为什么这段代码不能编译( Parent
是一个接口)?
Why this code does not compile (Parent
is an interface)?
List<? extends Parent> list = ...
Parent p = factory.get(); // returns concrete implementation
list.set(0, p); // fails here: set(int, ? extends Parent) cannot be applied to (int, Parent)
推荐答案
这是为了安全起见。想象一下它是否有效:
It's doing that for the sake of safety. Imagine if it worked:
List<Child> childList = new ArrayList<Child>();
childList.add(new Child());
List<? extends Parent> parentList = childList;
parentList.set(0, new Parent());
Child child = childList.get(0); // No! It's not a child! Type safety is broken...
List的含义<? extends Parent>
是这是一个扩展父类
的某种类型的列表。我们不知道哪种类型 - 它可能是 List< Parent>
,a List< Child>
或 List< GrandChild>
。这使得安全地获取 List< T>
API的任何项 out 并从 T $ c转换$ c> to
Parent
,但在中调用并不安全 List< T>
将API从父母
转换为 T
...,因为该转换可能无效。
The meaning of List<? extends Parent>
is "The is a list of some type which extends Parent
. We don't know which type - it could be a List<Parent>
, a List<Child>
, or a List<GrandChild>
." That makes it safe to fetch any items out of the List<T>
API and convert from T
to Parent
, but it's not safe to call in to the List<T>
API converting from Parent
to T
... because that conversion may be invalid.
这篇关于无法使用通配符泛型为Java集合添加值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!