如何使用正则表达式匹配任何重复的字符？ [英] how do I match a any repeating character using regexp?

问题描述

我需要匹配任何重复两次的字符，例如：

 abccdeff
  

匹配cc和ff。在任何其他正则表达式语法中，我们使用Javascript作为一个简单的例子，我可以这样做：

  var str =abccdeff; 
 var r = /（[az] {1}）\ 1 / g 
 console.log（str.match（r））
  

其中返回

  ['cc'，'ff'] 
  

但Go的正则表达式似乎不允许这样做。是否可以在Go中执行此操作？

解决方案

由于反向引用是不受re2支持，您需要：

• 要么使用另一个正则表达式库（如 glenn-brown / golang-pkg-pcre ）


• 或编写循环，无需regexp即可进行分析

ul>


I need to match any character that's repeated twice, for example:

"abccdeff"

Should match "cc" and "ff". In any other regex syntax, let's use Javascript as a quick example, I could do:

var str = "abccdeff";
var r = /([a-z]{1})\1/g
console.log(str.match(r))

Which returns

[ 'cc', 'ff' ]

But Go's regexp doesn't seem to allow that. Is it possible to do this in Go?

解决方案

Since backreference is not supported by re2, you would need:

• either to use another regex library (like glenn-brown/golang-pkg-pcre)
• or code a loop which does the analysis without regexp

这篇关于如何使用正则表达式匹配任何重复的字符？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！