正确地将参数传递给Go Exec [英] Properly pass arguments to Go Exec
问题描述
我正在努力学习,首先我想尝试把超级简单的网络服务器放在一起来控制我的iTunes。我过去曾多次使用 osascript -e'告诉应用程序iTunes以playpause'
多次,并认为我可以在这里简单地将呼叫拒绝给osascript。
I'm trying to learn go and as a start I wanted to try to throw together a super simple web server for controlling my iTunes. I've used osascript -e 'Tell Application "iTunes" to playpause'
to this purpose many times in the past and thought I could simply sluff the call off to osascript here.
注释掉say 5命令确实有效。
The commented out "say 5" command does work.
package main
import "exec"
//import "os"
func main() {
var command = "Tell Application 'iTunes' to playpause"
//var command = "say 5"
c := exec.Command("/usr/bin/osascript", "-e", command)
// c.Stdin = os.Stdin
_, err := c.CombinedOutput()
println(err.String());
}
我收到的回应是如下所示 -
The response I am receiving from this is as follows -
jessed@JesseDonat-MBP ~/Desktop/goproj » ./8.out
exit status 1
[55/1536]0x1087f000
我不确定该从哪里出发和任何方向将不胜感激。
I'm not exactly sure where to go from here and any direction would be greatly appreciated.
推荐答案
我得到它与此工作
package main
import (
"fmt"
"exec"
)
func main() {
command := "Tell Application \"iTunes\" to playpause"
c := exec.Command("/usr/bin/osascript", "-e", command)
if err := c.Run(); err != nil {
fmt.Println(err.String())
}
}
我认为exec.Command(...)会在参数中添加双引号,因此您只需在需要它们的地方转义\。
I think exec.Command(...) adds double quotes to the parameters if there is spaces in them, so you only need to escape \" where you need them.
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