如何检测Chrome中的弹出式窗口拦截器？ [英] How do I detect popup blocker in Chrome?

问题描述

我在堆栈溢出中搜索了很多问题，可能是重复的 检测弹出窗口

I have searched many issue in stack overflow and might be duplicate here Detect Popup

但对我没有帮助 Chrome中测试（测试v26.0.1410.64）

以下方法在IE和Firefox中工作但 not in Chrome

But not helped for me while testing in Chrome (tested v26.0.1410.64)
Following Approach Worked in IE and Firefox but not in Chrome

var popup = window.open(winPath,winName,winFeature,true);
 if (!popup || popup.closed || typeof popup.closed=='undefined'){
       //Worked For IE and Firefox
        alert("Popup Blocker is enabled! Please add this site to your exception list.");
        window.location.href = 'warning.html';
 } else {
        //Popup Allowed
        window.open('','_self');
        window.close();
} 

任何适用于Chrome的更好解决方案也是？

Any better solution that works for Chrome also?

推荐答案

最后，通过结合Stackoverflow的成员

的不同答案获得成功此代码适用于我&在 IE，Chrome& Firefox

Finally, it success by combining different answer from Stackoverflow's member
This code worked for me & tested in IE, Chrome & Firefox

var popup = window.open(winPath,winName,winFeature,true);
 setTimeout( function() {
    if(!popup || popup.outerHeight === 0) {
        //First Checking Condition Works For IE & Firefox
        //Second Checking Condition Works For Chrome
        alert("Popup Blocker is enabled! Please add this site to your exception list.");
         window.location.href = 'warning.html';
    } else {
        //Popup Blocker Is Disabled
        window.open('','_self');
        window.close();
    } 
}, 25);

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