Groovy最终意味着什么? [英] what does final mean in Groovy
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问题描述
如果您在Groovy控制台中运行以下代码,它会打印出8
class F {
private final Integer val = 2
def set(v){val = v}
def print(){println val}
}
def f = new F()
f.set(8)
f.print()
在Java中,这段代码不会编译,因为在构造函数运行后您不能分配 final 引用。我知道对于属性,
final
表示该属性不能在该类的外部更改,但是标记私有字段的含义是什么最后
?
谢谢,
Don
解决方案
看起来这可能是一个Groovy错误:
我不认为在初始化后应该赋值 val
p>
If you run the following code in the Groovy console it prints "8"
class F {
private final Integer val = 2
def set(v) {val = v}
def print() {println val}
}
def f = new F()
f.set(8)
f.print()
In Java this code wouldn't compile because you can't assign a final
reference after the constructor has run. I know that for properties, final
indicates that the property can't be changed outside the class, but what does it mean to mark a private field final
?
Thanks, Don
解决方案
It looks like this might be a Groovy bug:
I wouldn't think that val
should be assignable after initialization.
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