如何通过查询来连接PostgreSQL'组中的字符串字段的字符串? [英] How to concatenate strings of a string field in a PostgreSQL 'group by' query?

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问题描述

我正在寻找一种通过查询连接组内字段的字符串的方法。例如,我有一张表:

  ID COMPANY_ID员工
1 1安娜
2 1账单
3 2 Carol
4 2 Dave

我想按group_id得到像这样的东西:

  COMPANY_ID雇员
1 Anna,Bill
2 Carol,Dave

在mySQL中有一个内置函数来执行此操作 group_concat

解决方案

PostgreSQL 9.0或更高版本:



最新版本的Postgres(自2010年年底起)拥有 一个>功能,它将完成问题的要求,例如,让你指定分隔符字符串:

  SELECT company_id,string_agg(employee,',')
FROM mytable
GROUP BY company_id;

Postgres 9.0还增加了指定 ORDER BY 子句任何聚合表达式;否则,订单未定义。所以你现在可以这样写:

  SELECT company_id,string_agg(employee,','ORDER BY employee)
FROM mytable
GROUP BY company_id;

确实:

 选择string_agg(actor_name,','ORDER BY first_appearance)



PostgreSQL 8.4或后来:



PostgreSQL 8.4(2009年)介绍了聚合函数 array_agg(expression) ,它将这些值连接成一个数组。然后可以使用 array_to_string()给出所需的结果:

  SELECT company_id,array_to_string(array_agg(employee),',')
FROM mytable
GROUP BY company_id;对于9.0以前的版本,



string_agg



如果有人遇到这种情况,需要为9.0之前的数据库寻找兼容填充,可以在 string_agg 除了 ORDER BY 子句。



所以在下面的定义中,它应该和9中的一样.x Postgres DB:

  SELECT string_agg(name,';')AS semi_colon_separated_names FROM things; 

但这会是一个语法错误:

  SELECT string_agg(name,';'ORDER BY name)AS semi_colon_separated_names FROM things; 
- >错误:在ORDER处或附近出现语法错误

测试PostgreSQL 8.3。

  CREATE FUNCTION string_agg_transfn(text,text,text)
RETURNS文本AS
$$
BEGIN
IF $ 1 IS NULL THEN
RETURN $ 2;
ELSE
RETURN $ 1 || $ 3 || $ 2;
END IF;
END;
$$
语言plpgsql IMMUTABLE
COST 1;

CREATE AGGREGATE string_agg(text,text)(
SFUNC = string_agg_transfn,
STYPE = text
);



自定义变体(所有Postgres版本)



在9.0之前,没有内置聚合函数来连接字符串。最简单的自定义实现(Vajda Gabo在此邮件列表中发布的 等等)是使用内置的 textcat 函数(它位于 || 运算符后面) :
$ b $ pre $ CREATE AGGREGATE textcat_all(
basetype = text,
sfunc = textcat,
stype = text,
initcond =''
);

文档。 >这简单地将所有的字符串粘在一起,没有分隔符。为了在它们之间插入一个,而不是最后,你可能想要创建自己的连接函数并将其替换为上面的textcat。以下是我在8.3.12上进行测试的结果:

  CREATE FUNCTION commacat(acc text,instr text)返回文本AS $$ 
BEGIN
IF acc IS NULL OR acc =''THEN
RETURN instr;
ELSE
RETURN acc || ','|| INSTR;
END IF;
END;
$$语言plpgsql;

即使行中的值为null或空,该版本也会输出逗号,输出如下:

  a,b,c,,e,,g 



如果您希望删除多余的逗号以输出此内容:

  a,b,c,e,g 

然后添加一个 ELSIF 检查如下函数:

  CREATE FUNCTION commacat_ignore_nulls(acc text,instr text)返回文本AS $$ 
BEGIN
IF acc IS NULL OR acc =''THEN
RETURN instr;
ELSIF instr IS NULL或instr =''THEN
RETURN acc;
ELSE
RETURN acc || ','|| INSTR;
END IF;
END;
$$语言plpgsql;


I am looking for a way to concatenate the strings of a field within a group by query. So for example, I have a table:

ID   COMPANY_ID   EMPLOYEE
1    1            Anna
2    1            Bill
3    2            Carol
4    2            Dave

and I wanted to group by company_id to get something like:

COMPANY_ID   EMPLOYEE
1            Anna, Bill
2            Carol, Dave

There is a built-in function in mySQL to do this group_concat

解决方案

PostgreSQL 9.0 or later:

Recent versions of Postgres (since late 2010) have the string_agg(expression, delimiter) function which will do exactly what the question asked for, even letting you specify the delimiter string:

SELECT company_id, string_agg(employee, ', ')
FROM mytable
GROUP BY company_id;

Postgres 9.0 also added the ability to specify an ORDER BY clause in any aggregate expression; otherwise, the order is undefined. So you can now write:

SELECT company_id, string_agg(employee, ', ' ORDER BY employee)
FROM mytable
GROUP BY company_id;

Or indeed:

SELECT string_agg(actor_name, ', ' ORDER BY first_appearance)

PostgreSQL 8.4 or later:

PostgreSQL 8.4 (in 2009) introduced the aggregate function array_agg(expression) which concatenates the values into an array. Then array_to_string() can be used to give the desired result:

SELECT company_id, array_to_string(array_agg(employee), ', ')
FROM mytable
GROUP BY company_id;

string_agg for pre-9.0 versions:

In case anyone comes across this looking for a compatibilty shim for pre-9.0 databases, it is possible to implement everything in string_agg except the ORDER BY clause.

So with the below definition this should work the same as in a 9.x Postgres DB:

SELECT string_agg(name, '; ') AS semi_colon_separated_names FROM things;

But this will be a syntax error:

SELECT string_agg(name, '; ' ORDER BY name) AS semi_colon_separated_names FROM things;
--> ERROR: syntax error at or near "ORDER"

Tested on PostgreSQL 8.3.

CREATE FUNCTION string_agg_transfn(text, text, text)
    RETURNS text AS 
    $$
        BEGIN
            IF $1 IS NULL THEN
                RETURN $2;
            ELSE
                RETURN $1 || $3 || $2;
            END IF;
        END;
    $$
    LANGUAGE plpgsql IMMUTABLE
COST 1;

CREATE AGGREGATE string_agg(text, text) (
    SFUNC=string_agg_transfn,
    STYPE=text
);

Custom variations (all Postgres versions)

Prior to 9.0, there was no built-in aggregate function to concatenate strings. The simplest custom implementation (suggested by Vajda Gabo in this mailing list post, among many others) is to use the built-in textcat function (which lies behind the || operator):

CREATE AGGREGATE textcat_all(
  basetype    = text,
  sfunc       = textcat,
  stype       = text,
  initcond    = ''
);

Here is the CREATE AGGREGATE documentation.

This simply glues all the strings together, with no separator. In order to get a ", " inserted in between them without having it at the end, you might want to make your own concatenation function and substitute it for the "textcat" above. Here is one I put together and tested on 8.3.12:

CREATE FUNCTION commacat(acc text, instr text) RETURNS text AS $$
  BEGIN
    IF acc IS NULL OR acc = '' THEN
      RETURN instr;
    ELSE
      RETURN acc || ', ' || instr;
    END IF;
  END;
$$ LANGUAGE plpgsql;

This version will output a comma even if the value in the row is null or empty, so you get output like this:

a, b, c, , e, , g

If you would prefer to remove extra commas to output this:

a, b, c, e, g

Then add an ELSIF check to the function like this:

CREATE FUNCTION commacat_ignore_nulls(acc text, instr text) RETURNS text AS $$
  BEGIN
    IF acc IS NULL OR acc = '' THEN
      RETURN instr;
    ELSIF instr IS NULL OR instr = '' THEN
      RETURN acc;
    ELSE
      RETURN acc || ', ' || instr;
    END IF;
  END;
$$ LANGUAGE plpgsql;

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