启动的应用程序在特定的时间 [英] Start app at a specific time

问题描述

我在想，如果有可能（如果它是如何）启动我的应用程序在特定的时间，像一个闹钟其在特定时间熄灭。 比方说，我想我的应用程序启动在早上8，是feasable？

I was wondering if it's possible (and if it is how) to start up my app at a specific time, something like an alarmclock which goes off at a specific time. Let's say I want my app to start up at 8 in the morning, is that feasable ?

推荐答案

您可以用AlarmManager做到这一点，继承人一个简短的例子。首先，您需要设置报警：

You can do it with AlarmManager, heres a short example. First you need to set the alarm:

        AlarmManager am = (AlarmManager) con
            .getSystemService(Context.ALARM_SERVICE);

    Date futureDate = new Date(new Date().getTime() + 86400000);


    futureDate.setHours(8);
    futureDate.setMinutes(0);
    futureDate.setSeconds(0);


    Intent intent = new Intent(con, MyAppReciever.class);

    PendingIntent sender = PendingIntent.getBroadcast(con, 0, intent,
            PendingIntent.FLAG_UPDATE_CURRENT);

    am.set(AlarmManager.RTC_WAKEUP, futureDate.getTimeInMillis(), sender); 

接下来，你需要创建一些code进行reciever来执行应用程序：（即 - 开始你的应用程序）：

Next, You need to create a reciever with some code to execute your application: (ie- starting your app):

public class MyAppReciever extends BroadcastReceiver {

@Override
public void onReceive(Context context, Intent intent) {

    startActivity(new Intent(context, MyApp.class));
}

}

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