试图简化代码的斗争 [英] Struggle trying to simplify code

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本文介绍了试图简化代码的斗争的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下方法:

  mainFunction arg1 =http://someBaseUrl.com/++ arg1 
url1 x = mainFunction x ++/ subUrl1
url2 x = mainFunction x ++/ subUrl2
url3 x = mainFunction x ++/ subUrl3
url4 x = mainFunction x ++/ subUrl4

我的直觉告诉我必须简化它。但我无法弄清楚如何。



我不能这样做,因为它不一样:

  url1 =(mainFunction。)++/ subUrl1

您的建议?你可以这样做:

$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $' url sx = mainFunction x ++ s
url1 = url/ subUrl1
url2 = url/ subUrl2

etc ...

如果您真的要尽可能减少代码并避免调用 url 树时间,你可以使用这个技巧(但是,我不确定这是推荐)

  [url1,url2,url3,url4] =地图url [/ subUrl1,/ subUrl2,subUrl3,subUrl4] 

这将声明四个函数 url1 ,... url4


I have the following methods:

mainFunction arg1 = "http://someBaseUrl.com/" ++ arg1
url1 x = mainFunction x ++ "/subUrl1"
url2 x = mainFunction x ++ "/subUrl2"
url3 x = mainFunction x ++ "/subUrl3"
url4 x = mainFunction x ++ "/subUrl4"

My gut tells me that it has to be simplified. But I can't figure out how.

I can't do this, though, because it's not the same:

url1 = (mainFunction .) ++ "/subUrl1"

Your suggestions?

解决方案

You can do

url s x = mainFunction x ++ s
url1 = url "/subUrl1"
url2 = url "/subUrl2"

etc ...

If you really to write as less code as possible and avoid to call url tree times, you can use this trick (however, I'm not sure it is recommended)

[url1, url2, url3, url4] = map url ["/subUrl1", "/subUrl2", "subUrl3", "subUrl4"]

This will declare the four functions url1, ... url4.

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