用jquery或javascript简单分页 [英] Simple pagination with jquery or javascript
问题描述
因此,我创建了以下简单的html代码:
< div class =post-list>
< div class =post>
< h3> head1< / h3>
< p> Test1< / p>
< / div>
< div class =post>
< h3> head2< / h3>
< p> Test2< / p>
< / div>
< div class =post>
< h3> head3< / h3>
< p> Test3< / p>
< / div>
< div class =post>
< h3> head4< / h3>
< p> Test4< / p>
< / div>
< div class =post>
< h3> head5< / h3>
< p> Test5< / p>
< / div>
< div class =post>
< h3> head6< / h3>
< p> Test6< / p>
< / div>
< / div>
< div class =pagination>
< / div>
我是web开发中的新手,我不知道如何编写简单的
JavaScript或jQuery代码来分页工作。
在搜索互联网后,我还没有找到任何简单的解决方案。
感谢您的帮助: - )
< a href =#id =prev>上一页页面< / A>
< a href =#id =next>下一页< / a>
< div class =pagination>
< div class =postid =page1> <! - 我给每个页面一个ID。 - >
< h3> head1< / h3>
< p> Test1< / p>
< / div>
< div class =postid =page2>
< h3> head2< / h3>
< p> Test2< / p>
< / div>
< div class =postid =page3>
< h3> head3< / h3>
< p> Test3< / p>
< / div>
< div class =postid =page4>
< h3> head4< / h3>
< p> Test4< / p>
< / div>
< div class =postid =page5>
< h3> head5< / h3>
< p> Test5< / p>
< / div>
< div class =postid =page6>
< h3> head6< / h3>
< p> Test6< / p>
< / div>
< / div>
在这种情况下,您需要做的只是动态地隐藏每个页面,除了您想要看到的页面:
function showPage(page){
$('。pagination .post:not(#page'+ page +' )')。隐藏();
$('。pagination .post#page'+ page).show();
$ / code>
如果你想要下一个和上一个按钮,你可以轻松地这样做: / p>
函数prevPage(){
/jsfiddle.net/nv1y59Lu/1/rel =nofollow>示例小提琴
if(page == 1){
page = $('。分页.post')。长度;
} else {
page--;
}
showPage(page);
}
function nextPage(){
if(page == $('。pagination .post')。length){
page = 1;
} else {
page ++;
}
showPage(page);
$ b请注意,您需要存储页面的编号(我使用<
I want to include a "pagination" with jquery or javascript to my website.
Therefore, I have created the following simple html-code:
<div class="post-list"> <div class="post"> <h3> head1 </h3> <p> Test1 </p> </div> <div class="post"> <h3> head2 </h3> <p> Test2 </p> </div> <div class="post"> <h3> head3 </h3> <p> Test3 </p> </div> <div class="post"> <h3> head4 </h3> <p> Test4 </p> </div> <div class="post"> <h3> head5 </h3> <p> Test5 </p> </div> <div class="post"> <h3> head6 </h3> <p> Test6 </p> </div> </div> <div class="pagination"> </div>
I am Newbie in web development and I don't know how to write a simple javascript or jquery code to make a pagination work. After searching the internet I haven't found any simple solution for it.
Therefore, I would really appreciate it if you could tell me a jquery or javascirpt code that I can apply to this html code.
Thanks for any help :-)
解决方案Using jQuery:
<a href="#" id="prev">Prev page</a> <a href="#" id="next">Next page</a> <div class="pagination"> <div class="post" id="page1"> <!-- I gave every "page" an ID. --> <h3> head1 </h3> <p> Test1 </p> </div> <div class="post" id="page2"> <h3> head2 </h3> <p> Test2 </p> </div> <div class="post" id="page3"> <h3> head3 </h3> <p> Test3 </p> </div> <div class="post" id="page4"> <h3> head4 </h3> <p> Test4 </p> </div> <div class="post" id="page5"> <h3> head5 </h3> <p> Test5 </p> </div> <div class="post" id="page6"> <h3> head6 </h3> <p> Test6 </p> </div> </div>
All you need to do in this situation is dynamically hide every page except the one you want to see:
function showPage(page) { $('.pagination .post:not(#page'+page+')').hide(); $('.pagination .post#page'+page).show(); }
If you want next and previous buttons you can easily do so like this:
function prevPage() { if (page == 1) { page = $('.pagination .post').length; } else { page--; } showPage(page); } function nextPage() { if (page == $('.pagination .post').length) { page = 1; } else { page++; } showPage(page); }
Just note that you need to store the number of the page (I used
page
in the example) if you want to have next and previous buttons.这篇关于用jquery或javascript简单分页的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!