使用python urllib2获取位置标头的值 [英] getting value of location header using python urllib2

问题描述

当我使用urllib2并列出标题时，我看不到位置标题。

when I use urllib2,and list the headers,I cannot see the 'Location' header.

In [19]:p = urllib2.urlopen('http://www.example.com')


In [21]: p.headers.items()
Out[21]: 
[('transfer-encoding', 'chunked'),
 ('vary', 'Accept-Encoding'),
 ('server', 'Apache/2.2.3 (CentOS)'),
 ('last-modified', 'Wed, 09 Feb 2011 17:13:15 GMT'),
 ('connection', 'close'),
 ('date', 'Fri, 25 May 2012 03:00:02 GMT'),
 ('content-type', 'text/html; charset=UTF-8')]

如果我使用telnet和GET

If I use telnet and GET

telnet www.example.com 80
Trying 192.0.43.10...
Connected to www.example.com.
Escape character is '^]'.
GET / HTTP/1.0  
Host:www.example.com

HTTP/1.0 302 Found
Location: http://www.iana.org/domains/example/
Server: BigIP
Connection: close
Content-Length: 0

那么，使用urllib2，如何获得'Location'标题的值？

So, using urllib2 , how do I get the value of 'Location' header?

推荐答案

使用 geturl 从 urlopen 返回类文件对象的方法：

Use the geturl method on the returned file-like object from urlopen:

>>> f = urllib2.urlopen('http://www.example.com')
>>> f.geturl()
'http://www.iana.org/domains/example/'

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