Java汇总了任何数字 [英] Java Round up Any Number
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问题描述
我似乎无法找到我正在寻找的关于一个简单问题的答案:如何将任何数字舍入到最近的 int
?
例如,每当数字为0.2,0.7,0.2222,0.4324,0.9999时,我希望结果为1.
<到目前为止,我已经
int b =(int)Math.ceil(a / 100);
但它似乎没有完成这项工作。
解决方案
Math.ceil()
是要调用的正确函数。我猜 a
是 int
,这会使 a / 100
执行整数运算。请尝试 Math.ceil(a / 100.0)
。
int a = 142;
System.out.println(a / 100);
System.out.println(Math.ceil(a / 100));
System.out.println(a / 100.0);
System.out.println(Math.ceil(a / 100.0));
System.out.println((int)Math.ceil(a / 100.0));
输出:
1
1.0
1.42
2.0
2
I can't seem to find the answer I'm looking for regarding a simple question: how do I round up any number to the nearest int
?
For example, whenever the number is 0.2, 0.7, 0.2222, 0.4324, 0.99999 I would want the outcome to be 1.
So far I have
int b = (int) Math.ceil(a / 100);
It doesn't seem to be doing the job, though.
解决方案
Math.ceil()
is the correct function to call. I'm guessing a
is an int
, which would make a / 100
perform integer arithmetic. Try Math.ceil(a / 100.0)
instead.
int a = 142;
System.out.println(a / 100);
System.out.println(Math.ceil(a / 100));
System.out.println(a / 100.0);
System.out.println(Math.ceil(a / 100.0));
System.out.println((int) Math.ceil(a / 100.0));
Outputs:
1
1.0
1.42
2.0
2
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