无法为“AnyObject”类型调用初始化程序？没有争论 [英] Cannot invoke initializer for type 'AnyObject?' with no arguments

问题描述

我正在使用swift 3来构建一种聊天信使。
为了存储loggedIn Users，我尝试使用AnyObject类型的onject。

I am using swift 3 to build a type of chat messenger. To store loggedIn Users, I try to use an onject of type AnyObject.

    var loggedInUser = AnyObject?()

它出现以下错误：
ViewController.swift：29：24：无法调用没有参数的'AnyObject？'类型的初始值设定项

And it gives the following error: ViewController.swift:29:24: Cannot invoke initializer for type 'AnyObject?' with no arguments

推荐答案

AnyObject 是协议。

协议没有初始化程序。您永远不能通过 ProtocolName（）初始化协议实例。您必须为协议中的方法提供实现，并创建具有这些实现的类的实例。

Protocols don't have initializers. You can never initialize an instance of a protocol by ProtocolName(). You must provide implementations for the methods in the protocol, and create an instance of the class that has those implementations.

我认为它不适合存储记录在用户中作为 AnyObject 因为用户不仅仅是任何对象。用户是用户！

I don't think it is suitable to store the logged in user as an AnyObject because well, a user isn't just any object. A user is a user!

我认为你应该做的是创建一个名为 User 的结构/类，将登录用户存储为该类型的实例。

What I think you should do, is create a struct/class named User and store the logged-in user as an instance of that type.

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