打开'DEBUG'宏观值 [英] Turning on 'DEBUG' macro value

问题描述

在我的代码中，我想有条件地执行一些操作：

In my code, I want to conditionally perform a few operations with:

#ifdef DEBUG
NSLog(@"I'm in debug mode");
#endif

我已经配置了Project-> Edit Project Settings-> Build tab so 'DEBUG'被列为用户定义的设置，其值为1.在Configuration下拉列表中选择Debug。这仍然没有打开Debug构建的指令，虽然我认为它会做什么。

I've configured Project->Edit Project Settings->Build tab so that 'DEBUG' is listed as a User-Defined setting with a value of 1. Debug is selected in the Configuration dropdown. This still doesn't turn on the directive for the Debug build although I thought that's what it would do.

在构建阶段我还需要做什么才能允许为此？

What else do I need to do during the build stage to allow for this?

推荐答案

您需要为此设置编译器标志。

You need to set a compiler flag for that.

要执行此操作，请在目标上获取信息，确保已选择调试配置（而不是所有配置），并查找其他C标志和其他C ++标志（在Xcode 3.1中，这些在 GCC 4.2 - 语言下）。

To do it, Get Info on the target, make sure you have selected the Debug configuration (and not All Configurations), and look for Other C Flags and Other C++ Flags (in Xcode 3.1 these are under GCC 4.2 - Language).

然后将以下内容添加为值： -DDEBUG 两者。

Then add the following as a value: -DDEBUG for both.

这将定义预编译器的DEBUG来获取它。

This will define the DEBUG for the precompiler to pick it up.

这篇关于打开'DEBUG'宏观值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！