在Java中的空格上拆分字符串，除非在引号之间（即将\“hello world \”作为一个标记处理） [英] Split string on spaces in Java, except if between quotes (i.e. treat \"hello world\" as one token)

问题描述

如何根据空格拆分字符串，但是将带引号的子字符串作为一个单词？

How do I split a String based on space but take quoted substrings as one word?

示例：

Location "Welcome  to india" Bangalore Channai "IT city"  Mysore

它应该存储在 ArrayList 中

Location
Welcome to india
Bangalore
Channai
IT city
Mysore

推荐答案

方法如下：

String str = "Location \"Welcome  to india\" Bangalore " +
             "Channai \"IT city\"  Mysore";

List<String> list = new ArrayList<String>();
Matcher m = Pattern.compile("([^\"]\\S*|\".+?\")\\s*").matcher(str);
while (m.find())
    list.add(m.group(1)); // Add .replace("\"", "") to remove surrounding quotes.


System.out.println(list);

输出：

[Location, "Welcome  to india", Bangalore, Channai, "IT city", Mysore]

正则表达式只是说

• [^]       - 以以外的其他商品开头的代币


• \S *        - 后跟零个或多个非空格字符


• ...或...


• 。+？     - -symbol后跟任何内容，直到另一个。

• [^"]     - token starting with something other than "
• \S*       - followed by zero or more non-space characters
• ...or...
• ".+?"   - a "-symbol followed by whatever, until another ".

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