Java-提取两个特殊字符之间的字符串的一部分 [英] Java- Extract part of a string between two special characters

问题描述

我一直试图找出如何在两个特殊字符之间提取字符串的一部分'和'我一直在研究正则表达式，但坦率地说我无法理解它。

Java中的示例代码：

I have been trying to figure out how to extract a portion of a string between two special characters ' and " I've been looking into regex, but frankly I cannot understand it.
Example in Java code:

String str="21*90'89\""; 

我想退出89

一般来说，我想知道如何在两个特定字符之间提取字符串的一部分。

In general I would just like to know how to extract part of a string between two specific characters please.

此外，如果知道如何提取部分字符串，那将会很高兴。从开头到特定字符的字符串，比如得到21。

Also it would be nice to know how to extract part of the string from the beginning to a specific character like to get 21.

推荐答案

试试这个正则表达式：

'(.*?)"

作为Java字符串文字，您必须按如下方式编写：

As a Java string literal you will have to write it as follows:

"'(.*?)\""

这是一个更完整的示例，演示了如何将此正则表达式与<$ c $一起使用c>匹配器：

Here is a more complete example demonstrating how to use this regular expression with a Matcher:

Pattern pattern = Pattern.compile("'(.*?)\"");
Matcher matcher = pattern.matcher(str);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

看到它在线工作： ideone

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