IllegalArgumentException:RestTemplate没有足够的变量值吗? [英] IllegalArgumentException: Not enough variable values available with RestTemplate?
问题描述
我试图像这样使用RestTemplate执行URL -
I am trying to execute URL using RestTemplate like this -
public static void main(String[] args) throws UnsupportedEncodingException {
RestTemplate restTemplate = new RestTemplate();
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0";
try {
String response = restTemplate.getForObject(url, String.class);
System.out.println(response);
} catch (RestClientException ex) {
ex.printStackTrace();
}
}
但每次我收到这样的错误 -
But everytime I am getting error like this -
Exception in thread "main" java.lang.IllegalArgumentException: Not enough variable values available to expand '@resourceId'
at org.springframework.web.util.UriComponents$VarArgsTemplateVariables.getValue(UriComponents.java:272)
什么我正在做错了以及如何修复它?
What is wrong I am doing and how to fix it?
更新: -
我也试过这个网址,它对我不起作用。我刚刚用 {{@ resourceId}}
I tried with this url as well and it didn't worked for me. I just replaced {@resourceId}
with {{@resourceId}}
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{{@resourceId}}?allowScan=true&limit=10000&skip=0";
更新-2
这是代码 -
try {
UriComponentsBuilder builder = UriComponentsBuilder
.fromPath("http://ptr.vip.str.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0");
UriComponents uriComponents = builder.build();
URI uri = uriComponents.toUri();
String response = restTemplate.getForObject(uri, String.class);
System.out.println(response);
} catch (RestClientException ex) {
ex.printStackTrace();
}
错误是 -
Exception in thread "main" java.lang.IllegalArgumentException: URI is not absolute
at java.net.URI.toURL(URI.java:1095)
at org.springframework.http.client.SimpleClientHttpRequestFactory.createRequest(SimpleClientHttpRequestFactory.java:109)
at org.springframework.http.client.support.HttpAccessor.createRequest(HttpAccessor.java:76)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:479)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:460)
at org.springframework.web.client.RestTemplate.getForObject(RestTemplate.java:228)
推荐答案
似乎 RestTemplate
有一种忽略 {...}
的方法。相反,从 String
值生成 URI
(不包含双
It doesn't seem like RestTemplate
has a means of ignoring {...}
. Instead, generate a URI
from your String
value (without the double {}
).
String url = "http://ptr.vip.host.com/pss/repositories/pssdb/branches/main/query/Service[@alias="
+ "hello"
+ "].serviceInstances.runsOn{@resourceId}?allowScan=true&limit=10000&skip=0";
UriComponentsBuilder builder = UriComponentsBuilder.fromPath(url);
UriComponents uriComponents = builder.build();
URI uri = uriComponents.toUri();
并使用重载的 getForObject
方法一个 URI
。
and use the overloaded getForObject
method which takes a URI
.
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