joda.time.DateTime反序列化错误 [英] joda.time.DateTime deserialization error
问题描述
我尝试将DateTime反序列化为attibute:
I tried to deserialize a class with a DateTime as attibute:
import org.joda.time.DateTime;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer;
import com.fasterxml.jackson.datatype.joda.ser.DateTimeSerializer;
class MyClass {
private DateTime alertTimestamp;
private String name;
@JsonSerialize(using = DateTimeSerializer.class)
public DateTime getAlertTimestamp() {
return alertTimestamp;
}
@JsonDeserialize(using = DateTimeDeserializer.class)
public void setAlertTimestamp(DateTime now) {
this.alertTimestamp = now;
}
//...
}
<但是,当我尝试反序列化时,我有这个例外:
But when I try tro deserialize, I have this exception:
com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer has no default (no arg) constructor
我用它来反序列化:
ObjectMapper mapper = new ObjectMapper();
mapper.readValue(jsonData, MyClass.class);
我的jsonData示例:
And an example of my jsonData:
{
"name":"test",
"alertTimestamp": {"year":2014,"era":1,"dayOfMonth":24,"dayOfWeek":1,"dayOfYear":83,"weekOfWeekyear":13,"weekyear":2014,"monthOfYear":3,"yearOfEra":2014,"yearOfCentury":14,"centuryOfEra":20,"millisOfSecond":232,"millisOfDay":45143232,"secondOfMinute":23,"secondOfDay":45143,"minuteOfHour":32,"minuteOfDay":752,"hourOfDay":12,"zone":{"uncachedZone":{"cachable":true,"fixed":false,"id":"America/Los_Angeles"},"fixed":false,"id":"America/Los_Angeles"},"millis":1395689543232,"chronology":{"zone":{"uncachedZone":{"cachable":true,"fixed":false,"id":"America/Los_Angeles"},"fixed":false,"id":"America/Los_Angeles"}},"afterNow":false,"beforeNow":false,"equalNow":true}
}
推荐答案
@JsonDeserialize
期望带有无参数的 JsonDeserializer
构造函数。最新版本的 DateTimeDeserializer
没有这样的构造函数。
@JsonDeserialize
expects a JsonDeserializer
with a no-arg constructor. The most recent version of DateTimeDeserializer
does not have such a constructor.
如果你已经修改了格式,即。 alertTimestamp
应该只是一个时间戳,然后您只需使用 ObjectMapper <注册
JodaModule
/ code>。它将在 DateTime
字段内部使用 DateTimeDeserializer
。你可以摆脱 @JsonDeserialize
注释。
If you've fixed the format, ie. alertTimestamp
should just be a timestamp, then you could simply register the JodaModule
with the ObjectMapper
. It will use DateTimeDeserializer
internally for DateTime
fields. You can get rid of the @JsonDeserialize
annotations.
mapper.registerModule(new JodaModule());
你需要添加 jackson-datatype-joda
library。
You'll need to add the jackson-datatype-joda
library.
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