在Python中知道int的字节的方法[带有位类引入] [英] Way to know bytes of an int in Python [with bits class thrown in]

问题描述

我需要知道数字的字节。例如，让我们假设我有


i = 3000


我想知道是否有办法获得单身数字的字节（0x0B和0xB8）。


提前致谢，

Daniele

解决方案

< blockquote>

我需要知道数字的字节。例如，让我们假设我有


i = 3000


我想知道是否有办法获得单身数字的字节（0x0B和0xB8）。


提前致谢，

Daniele

展开 < span class =codeDivider> | 选择 | Wrap | Line数字

只是一个好奇心，但是有没有内置的转换为二进制？例如：

3000 =''101110111000''

首先，谢谢，


lowbyte来自


lowByte =''0x％s''％bytes [2：4]


我发现了另一个解决方案：

展开 | 选择 | Wrap | 行号

Hi,

I need to know the byte which a number is made of. For example, let''s suppose I have

i = 3000

I would like to know if there is a way to get the single byte of the number (0x0B and 0xB8).

Thanks in advance,
Daniele

解决方案

Hi,

I need to know the byte which a number is made of. For example, let''s suppose I have

i = 3000

I would like to know if there is a way to get the single byte of the number (0x0B and 0xB8).

Thanks in advance,
Daniele

Expand|Select|Wrap|Line Numbers

Just a curiosity but is there any built-in that would convert to binary? For example:
3000=''101110111000''

First of all thanks,

the lowbyte comes from

lowByte = ''0x%s'' % bytes[2:4]

I''ve found also another solution:

Expand|Select|Wrap|Line Numbers

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