排序数组 [英] sorting an array

问题描述

如果我有这样定义的数组：


var list = [

[" 1"，" 359"，" No a test xxxxxxxxxxxxxxx"，"

0"，08 / 18/2003，Approved，

[" 2"，" 268" ;，测试字符字段为500

，129，07/14/2003，已批准，

[" ; 3，288，textarea填充XXXXXXXx，

0，07/15/2003，已批准]

];


如何在第3栏排序？


迈克

解决方案

Michael Hill< hi **** @ ram.lmtas.lmco.com>写道：

如果我有一个这样定义的数组：

var list = [
[" 1"，" 359"， No a Test xxxxxxxxxxxxxxx，
0，08/18/2003，Approved，

请避免发布代码时换行符。发布的代码是

无效。


试试这个：

---

函数比较（a，b）{

if（a< b）{return -1;}

if（a> b）{return 1;}

返回0;

}


var sortedList = list.sort（function（a，b）{return compare（a [2 ]，b [2]）;}）;

---


/ L

-

Lasse Reichstein Nielsen - lr*@hotpop.com

DHTML死亡颜色：< URL：http ：//www.infimum.dk/HTML/rasterTriangleDOM.html>

''没有判断的信仰只会降低精神神圣。''

>如果我有这样定义的数组：

var list = [
[" 1"，" 359"，No a Test xxxxxxxxxxxxxxx，"
0"，08/18/2003，Approved，
[" 2"，268，测试字符字段为500
，129，07/14/2003，已批准，
[" 3"，" 288"，" textarea filled XXXXXXXx"，"
0" ;，07/15/2003，已批准，
;

如何按第3列排序？

您可以将函数传递给array.sort（fn）方法。


list.sort（函数（a，b）{

if（a [2] == b [2]）{

返回0;

}

if（a [2] < b [2]）{

返回-1;

}

返回1;

}） ;


// 15.4.4.11

http://www.crockford.com/javascript/survey.html

Douglas Crockford在2003年12月1日写了comp.lang.javascript ：

list.sort（function（a，b）{
if（ a [2] == b [2]）{
返回0;
}
if（a [2]< b [2]）{
返回-1;
}
返回1;
}）;

In简短：


list.sort（

函数（a，b）{

return（a [2]> b [2]）？1：（a [2]< b [2]）？ - 1：0

}

）;

-

Evertjan。

荷兰。

（请在我的电子邮件地址中将x'变为点数）

If I have an array defined like this:

var list = [
["1","359","No a Test xxxxxxxxxxxxxxx","
0","08/18/2003","Approved"],
["2","268","test character fields for 500
","129","07/14/2003","Approved"],
["3","288","textarea filled XXXXXXXx","
0","07/15/2003","Approved"]
];

How would I sort it by the 3th column?

Mike

解决方案

Michael Hill <hi****@ram.lmtas.lmco.com> writes:

If I have an array defined like this:

var list = [
["1","359","No a Test xxxxxxxxxxxxxxx","
0","08/18/2003","Approved"],

Please avoid line breaks when posting code. The code, as posted, is
invalid.

Try this:
---
function compare(a,b) {
if (a<b) {return -1;}
if (a>b) {return 1;}
return 0;
}

var sortedList = list.sort(function(a,b){return compare(a[2],b[2]);});
---

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleDOM.html>
''Faith without judgement merely degrades the spirit divine.''

> If I have an array defined like this:

var list = [
["1","359","No a Test xxxxxxxxxxxxxxx","
0","08/18/2003","Approved"],
["2","268","test character fields for 500
","129","07/14/2003","Approved"],
["3","288","textarea filled XXXXXXXx","
0","07/15/2003","Approved"]
];

How would I sort it by the 3th column?

You can pass a function to the array.sort(fn) method.

list.sort(function (a, b) {
if (a[2] == b[2]) {
return 0;
}
if (a[2] < b[2]) {
return -1;
}
return 1;
});

// 15.4.4.11

http://www.crockford.com/javascript/survey.html

Douglas Crockford wrote on 01 dec 2003 in comp.lang.javascript:

list.sort(function (a, b) {
if (a[2] == b[2]) {
return 0;
}
if (a[2] < b[2]) {
return -1;
}
return 1;
});

In short:

list.sort(
function(a,b) {
return (a[2]>b[2])?1:(a[2]<b[2])?-1:0
}
);
--
Evertjan.
The Netherlands.
(Please change the x''es to dots in my emailaddress)

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