KornShell整数排序数组 [英] KornShell Sort Array of Integers

问题描述

KornShell(ksh)脚本中是否有命令来对整数数组进行排序?在这种特定情况下，我对简单性而非效率感兴趣.例如，如果变量$ UNSORTED_ARR包含值"100911、111228、090822"，而我想将结果存储在$ SORTED_ARR

Is there a command in KornShell (ksh) scripting to sort an array of integers? In this specific case, I am interested in simplicity over efficiency. For example if the variable $UNSORTED_ARR contained values "100911, 111228, 090822" and I wanted to store the result in $SORTED_ARR

推荐答案

它实际上是索引数组还是字符串列表?

Is it actually an indexed array or a list in a string?

数组:

UNSORTED_ARR=(100911 111228 090822)
SORTED_ARR=($(printf "%s\n" ${UNSORTED_ARR[@]} | sort -n))

字符串:

UNSORTED_ARR="100911, 111228, 090822"
SORTED_ARR=$(IFS=, printf "%s\n" ${UNSORTED_ARR[@]} | sort -n | sed ':a;$s/\n/,/g;N;ba')

还有其他几种方法可以做到这一点，但是原理是相同的.

There are several other ways to do this, but the principle is the same.

这是使用另一种技术的字符串的另一种方式:

Here's another way for a string using a different technique:

set -s -- ${UNSORTED_ARR//,}
SORTED_ARR=$@
SORTED_ARR=${SORTED_ARR// /, }

请注意，这是一种 lexicographic 排序方式，因此当数字没有前导零时，您会看到这种情况:

Note that this is a lexicographic sort so you would see this kind of thing when the numbers don't have leading zeros:

$ set -s -- 10 2 1 100 20
$ echo $@
1 10 100 2 20

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