排序数组字典 [英] Sort array into dictionary

问题描述

我有许多字符串数组。
我wan't将它们整理成一本字典，所以所有开始同一封信去到一个数组，然后数组成为一个关键的字符串值;关键是与其中的所有词的价值的数组开头字母。

示例

 键=A＆GT;＆GT;值=数组=苹果，动物，字母，ABC ......
答案=B＆GT;＆GT;值=数组=蝙蝠，球，香蕉......
 

我怎样才能做到这一点？
非常感谢事先！

解决方案

 的NSArray *名单= [NSArray的arrayWithObjects：@苹果，动物，蝙蝠，球，零]
*的NSMutableDictionary字典=的NSMutableDictionary字典]
对于（的NSString *单词）{
    的NSString * firstLetter = [[字substringToIndex：1] uppercaseString];
    NSMutableArray里* letterList = [字典objectForKey：firstLetter];
    如果（！letterList）{
        letterList = [NSMutableArray的阵列]
        [字典的setObject：letterList forKey：firstLetter];
    }
    [letterList ADDOBJECT：字]。
}
的NSLog（@％@，字典）;
 

I have and array of many strings. I wan't to sort them into a dictionary, so all strings starting the same letter go into one array and then the array becomes the value for a key; the key would be the letter with which all the words in it's value's array begin.

Example

Key = "A" >> Value = "array = apple, animal, alphabet, abc ..."
Key = "B" >> Value = "array = bat, ball, banana ..."

How can I do that? Thanks a lot in advance!

解决方案

NSArray *list = [NSArray arrayWithObjects:@"apple, animal, bat, ball", nil];
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
for (NSString *word in list) {
    NSString *firstLetter = [[word substringToIndex:1] uppercaseString];
    NSMutableArray *letterList = [dict objectForKey:firstLetter];
    if (!letterList) {
        letterList = [NSMutableArray array];
        [dict setObject:letterList forKey:firstLetter];
    }
    [letterList addObject:word];
}
NSLog(@"%@", dict);

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