复制列表中的元素 [英] replicating elements in list

问题描述

说我有这个

b = 3
l = [1, 2]

我想修改l，以便每个元素出现与b一样多的次数.这样:

I want to modify l so that each element appears as many times as b. So that:

l = [1, 1, 1, 2, 2, 2]

我用了这个:

for x in l:
  for m in range(b):
    l.append(x)

但是它导致了无限循环. 任何帮助，将不胜感激. 我希望你们提供想法而不是给我代码. 谢谢.

But it resulted in an infinite loop. Any help would be appreciated. I would prefer you guys to give ideas rather than give me the code. Thanks.

推荐答案

我的2美分:

另一种实现此目的的方法是利用您可以在Python中将列表相乘的事实.

Another way to achieve this would also be to take advantage of the fact you can multiply lists in Python.

>>> l = [1, 2, 3]
>>> [1, 2, 3] * 3
[1, 2, 3, 1, 2, 3, 1, 2, 3]

只需调用sorted函数即可对其进行排序:

A simple call to the sorted function allows to sort it back :

>>> b = 3    
>>> l = [1, 2]
>>> sorted(l * b)
[1, 1, 1, 2, 2, 2]

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