python，按键对列表进行排序，键是每个元素的子字符串 [英] python, sorting a list by a key that's a substring of each element

问题描述

程序的一部分将构建此列表，

Part of a programme builds this list,

[u'1 x Affinity for war', u'1 x Intellect', u'2 x Charisma', u'2 x Perception', u'3 x Population growth', u'4 x Affinity for the land', u'5 x Morale']

我目前正在尝试按演变名称而不是数字按字母顺序对其进行排序.我有什么办法可以做到而又不改变这两个东西在列表中的显示顺序(如'intellect x 1)?

I'm currently trying to sort it alphabetically by the name of the evolution rather than by the number. Is there any way I can do this without just changing the order the two things appear in the list (as in 'intellect x 1)?

推荐答案

您必须从字符串中获取键".

You have to get the "key" from the string.

def myKeyFunc( aString ):
    stuff, x, label = aString.partition(' x ')
    return label

aList.sort( key= myKeyFunc )

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