当键是字符串(名称)时，按字母顺序对字典进行排序 [英] Sort dictionary alphabetically when the key is a string (name)

问题描述

首先，我知道有很多关于字典排序的帖子，但是我找不到适合我的情况的帖子-而且我只是不了解sorted(... lambda)的内容-因此，请继续.

First, I know there are a LOT of posts on dictionary sorting but I couldn't find one that was exactly for my case - and I am just not understanding the sorted(...lambda) stuff - so here goes.

使用Python 3.x，我有一个像这样的字典:

Using Python 3.x I have a dictionary like this:

dictUsers[Name] = namedTuple(age, address, email, etc...)

例如，我的字典看起来像

So as an example my dictionary looks like

[John]="29, 121 bla, [e-mail]"
[Jack]="32, 122 ble, [e-mail]"
[Rudy]="42, 123 blj, [e-mail]"

现在要进行打印，请执行以下操作(响应是一个字典):

And right now for printing I do the following (where response is a dictionary):

for keys, values in response.items():
    print("Name= " + keys)
    print ("   Age= " + values.age)
    print ("   Address= " + values.address)
    print ("   Phone Number= " + values.phone)

当用户要求打印出用户数据库时，我希望它根据用作密钥的名称"以字母顺序打印.

And when the user asks to print out the database of users I want it to print in alphabetical order based on the "name" which is used as the KEY.

我可以使用所有的东西-但是没有排序-在开始手动排序之前，我想也许有内置的方法...

I got everything to work - but it isn't sorted - and before starting to sort it manually I thought maybe there was a built-in way to do it ...

谢谢

推荐答案

一种简单的算法，用于按字母顺序对字典键进行排序，首先使用sorted

simple algorithm to sort dictonary keys in alphabetical order, First sort the keys using sorted

sortednames=sorted(dictUsers.keys(), key=lambda x:x.lower())

对于每个键名，检索字典中的值

for each key name retreive the values from the dict

for i in sortednames:
   values=dictUsers[i]
   print("Name= " + i)
   print ("   Age= " + values.age)
   print ("   Address= " + values.address)
   print ("   Phone Number= " + values.phone)

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