当字符串是数字时，如何在考虑值的同时按字母顺序对字符串进行排序? [英] How do I sort strings alphabetically while accounting for value when a string is numeric?

问题描述

我正在尝试对作为字符串的数字数组进行排序，并且我希望它们按数字进行排序.

I'm trying to sort an array of numbers that are strings and I'd like them to sort numerically.

问题在于我无法将数字转换为 int.

代码如下:

string[] things= new string[] { "105", "101", "102", "103", "90" };

foreach (var thing in things.OrderBy(x => x))
{
    Console.WriteLine(thing);
}

输出:

101, 102, 103, 105, 90

我愿意:

90, 101, 102, 103, 105

输出不能是 090, 101, 102...

将代码示例更新为things"；而不是sizes".数组可以是这样的:

Updated the code sample to say "things" instead of "sizes". The array can be something like this:

string[] things= new string[] { "paul", "bob", "lauren", "007", "90" };

这意味着它需要按字母顺序和数字排序:

That means it needs to be sorted alphabetically and by number:

007, 90, bob, lauren, paul

推荐答案

将自定义比较器传递给 OrderBy.Enumerable.OrderBy 可让您指定任何您喜欢的比较器.

Pass a custom comparer into OrderBy. Enumerable.OrderBy will let you specify any comparer you like.

这是一种方法:

void Main()
{
    string[] things = new string[] { "paul", "bob", "lauren", "007", "90", "101"};

    foreach (var thing in things.OrderBy(x => x, new SemiNumericComparer()))
    {    
        Console.WriteLine(thing);
    }
}


public class SemiNumericComparer: IComparer<string>
{
    /// <summary>
    /// Method to determine if a string is a number
    /// </summary>
    /// <param name="value">String to test</param>
    /// <returns>True if numeric</returns>
    public static bool IsNumeric(string value)
    {
        return int.TryParse(value, out _);
    }

    /// <inheritdoc />
    public int Compare(string s1, string s2)
    {
        const int S1GreaterThanS2 = 1;
        const int S2GreaterThanS1 = -1;

        var IsNumeric1 = IsNumeric(s1);
        var IsNumeric2 = IsNumeric(s2);

        if (IsNumeric1 && IsNumeric2)
        {
            var i1 = Convert.ToInt32(s1);
            var i2 = Convert.ToInt32(s2);

            if (i1 > i2)
            {
                return S1GreaterThanS2;
            }

            if (i1 < i2)
            {
                return S2GreaterThanS1;
            }

            return 0;
        }

        if (IsNumeric1)
        {
            return S2GreaterThanS1;
        }

        if (IsNumeric2)
        {
            return S1GreaterThanS2;
        }

        return string.Compare(s1, s2, true, CultureInfo.InvariantCulture);
    }
}

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