如何返回字典中的最小值? [英] How to return smallest value in dictionary?

问题描述

让我说一本关于水果的字典:

Let say I have a dictionary of total of fruits:

Fruits = {"apple":8, "banana":3, "lemon":5, "pineapple":2,}

我希望输出为

["pineapple"]

因为菠萝的价值最小.或者，如果我有这个:

because pineapple has the least value. Or if i have this:

Colour = {"blue":5, "green":2, "purple":6, "red":2}

输出将是:

["green","red"]

因为绿色和红色的值都最小.

because green and red has both the least value.

那么如何返回字典中的最小值?

So how do I return the smallest value in dictionary?

推荐答案

可以通过两次通过:

>>> colour
{'blue': 5, 'purple': 6, 'green': 2, 'red': 2}
>>> min_val = min(colour.itervalues())
>>> [k for k, v in colour.iteritems() if v == min_val]
['green', 'red']

1. 找到字典值的最小值
2. 然后返回并提取该值所在的键...

另一种选择(需要一些导入，并且如果需要，您可以采用n个)-此代码仅采用第一个(这是最小值):

An alternative (requires some imports, and means you could take the n many if wanted) - this code just takes the first though (which would be the min value):

from itertools import groupby
from operator import itemgetter

ordered = sorted(colour.iteritems(), key=itemgetter(1))
bykey = groupby(ordered, key=itemgetter(1))
print map(itemgetter(0), next(bykey)[1])
# ['green', 'red']

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