如何返回对应于字典中最小值的键列表 [英] How to return a list of keys corresponding to the smallest value in dictionary

问题描述

让我说一本关于水果总数的字典：

Let say I have a dictionary of total of fruits:

Fruits = {"apple":8, "banana":3, "lemon":5, "pineapple":2,}

我希望输出为

["pineapple"]

菠萝的价值最小。或者，如果我有这个：

because pineapple has the least value. Or if I have this:

Colour = {"blue":5, "green":2, "purple":6, "red":2}

输出将是：

["green","red"]

因为绿色和红色都具有

那么如何返回字典中的最小值？

So how do I return the smallest value in dictionary?

推荐答案

可以通过两次通过：

>>> colour
{'blue': 5, 'purple': 6, 'green': 2, 'red': 2}
>>> min_val = min(colour.itervalues())
>>> [k for k, v in colour.iteritems() if v == min_val]
['green', 'red']

1. 找到字典值的最小值


2. 然后返回并提取该值所在的键。 。

另一种方法（需要一些导入，如果需要，您可以选择n个）-该代码只需要第一个（这将是最小值）：

An alternative (requires some imports, and means you could take the n many if wanted) - this code just takes the first though (which would be the min value):

from itertools import groupby
from operator import itemgetter

ordered = sorted(colour.iteritems(), key=itemgetter(1))
bykey = groupby(ordered, key=itemgetter(1))
print map(itemgetter(0), next(bykey)[1])
# ['green', 'red']

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