bash创建具有序号的目录 [英] bash create dir with sequential numbers

问题描述

我正在创建一个要在OS X上运行的脚本，该脚本通常由新手用户运行，因此想通过每次创建一个新的脚本来保护目录结构，最后一次创建一个n + 1:

I am creating a script to run on OS X which will be run often by a novice user, and so want to protect a directory structure by creating a fresh one each time with an n+1 over the last:

target001，下一次运行将创建target002

target001 with the next run creating target002

我到目前为止:

lastDir=$(find /tmp/target* | tail -1 | cut -c 6-)
let n=$n+1
mkdir "$lastDir""$n"

但是，数学在这里不起作用.

However, the math isn't working here.

推荐答案

没有管道和子进程:

targets=( /tmp/target* )                # all dirs in an array
lastdir=${targets[@]: (-1):1}           # select filename from last array element
lastdir=${lastdir##*/}                  # remove path
lastnumber=${lastdir/target/}           # remove 'target'
lastnumber=00$(( 10#$lastnumber + 1 ))  # increment number (base 10), add leading zeros

mkdir /tmp/target${lastnumber: -3}      # make dir; last 3 chars from lastnumber

具有2个参数的版本:

path='/tmp/x/y/z'                       # path without last part
basename='target'                       # last part

targets=( $path/${basename}* )          # all dirs in an array
lastdir=${targets[@]: (-1):1}           # select path from last entry
lastdir=${lastdir##*/}                  # select filename
lastnumber=${lastdir/$basename/}        # remove 'target'
lastnumber=00$(( 10#$lastnumber + 1 ))  # increment number (base 10), add leading zeros

mkdir $path/$basename${lastnumber: -3}  # make dir; last 3 chars from lastnumber

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