元音计数顺序 [英] Sequence of vowels count

问题描述

这不是家庭作业问题，是考试准备问题.

This is not a homework question, it is an exam preparation question.

我应该定义一个函数syllables(word)来计算其中的音节数量 用以下方式一个词:

I should define a function syllables(word) that counts the number of syllables in A word in the following way:

•最大的元音序列是一个音节；

• a maximal sequence of vowels is a syllable;

•单词中的最后一个 e 不是一个音节(或者它是元音序列的一部分) 的.

• a final e in a word is not a syllable (or the vowel sequence it is a part Of).

我不必处理任何特殊情况，例如 一个音节的单词(例如"be"或"bee").

I do not have to deal with any special cases, such as a final e in a One-syllable word (e.g., ’be’ or ’bee’).

>>> syllables(’honour’)
2
>>> syllables(’decode’)
2
>>> syllables(’oiseau’)
2

我应该在这里使用正则表达式还是只是列表理解?

Should I use regular expression here or just list comprehension ?

推荐答案

我发现此问题很自然的正则表达式. (我认为，非正则表达式的答案将需要更多的编码.我使用两种字符串方法("lower"和"endswith"来使答案更清晰).

I find regular expressions natural for this question. (I think a non-regex answer would take more coding. I use two string methods, 'lower' and 'endswith' to make the answer more clear.)

import re
def syllables(word):
    word = word.lower()
    if word.endswith('e'):
        word = word[:-1]
    count = len(re.findall('[aeiou]+', word))
    return count

for word in ('honour', 'decode', 'decodes', 'oiseau', 'pie'):
    print word, syllables(word)

哪些印刷品:

honour 2
decode 2
decodes 3
oiseau 2
pie 1

请注意，解码"的音节比解码"多(这很奇怪，但符合您的定义).

Note that 'decodes' has one more syllable than 'decode' (which is strange, but fits your definition).

问题.这对您有什么帮助?学习问题不是您自己亲自研究的重点吗?通过在问题中进行失败的尝试，将来可能会获得更多好处，因此您可以确切地了解自己所缺少的地方.

Question. How does this help you? Isn't the point of the study question that you work through it yourself? You may get more benefit in the future by posting a failed attempt in your question, so you can learn exactly where you are lacking.

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