为什么这个代码不仅计数元音？ [英] Why does this code not only count vowels?

问题描述

必须调试此类的某段代码，我无法弄清楚为什么这个JS计数所有的字母，而不仅仅是元音。

Have to debug a certain segment of code for this class and I can't figure out why this JS counts all letters and not just vowels.

var text, i, sLength, myChar;
var count;
var text = prompt("Type a phrase please"); //put var in front of text and   fixed " in place of ' in front of type
count = 0;
for (i = 1; i <= text.length; i+= 1){
    myChar = text[i];
    if (myChar == 'a' || 'o' || 'e' || 'u'){ //switched to the proper vowels
        count += 1;
        console.log('Vowel:', myChar);   
    }
    console.log(myChar, count);
}
alert (count); //put the count in () instead of alert

推荐答案

超短路

Super Short Way

function countVowels (string) {
    return string.match(/a|e|i|o|u/g).length;
}

用作： / p>

Use as:

alert(countVowels(prompt("Type a phrase please")));

---

如果是无效的条件，您是希望快速检查一个值是否是某些选项之一，请尝试以下操作：

---

You're if is an invalid condition. If you wish to quickly check if a value is one of some options, try the following:

if (['a', 'e', 'i', 'o', 'u'].indexOf(myChar) > -1) {
}

function hasOptions (c) {
    return arguments.splice(1).indexOf(c);
}

然后

if (hasOptions(myChar, 'a', 'e', 'i', 'o', 'u'))

这篇关于为什么这个代码不仅计数元音？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！