Swift中的元音计数 [英] Counting Vowels in Swift

问题描述

我已经在Java和C ++中成功完成了此操作，但是在Swift中却无法解决.这是我的C ++代码:

I have done this successfully in Java and C++ but can't figure it out in Swift. Here is my C++ code:

int count_vowels (string input)
{
  int position = 0;

  for (int i = 0; i < input.length(); i++)
    {
    char ch;
    ch = input[i];

      if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u'){
          position++;
      }

  }
  return position;
}

再次，我只是尝试遍历一个字符串，计算if语句中为true的值，然后返回位置(有多少个).

Again I'm just trying to iterate through a string, counting the values that are true in the if statement and returning the position(how many there are).

有什么方法可以将其转换为快速语法.

Is there any way to convert this to swift syntax.

我知道了:

用于元音字符中的字符{

for char in vowels.characters{

            if char == ("a") || char == ("e") || char == ("i") || char == ("o") || char == ("u") {

                count++
            }
    }

谢谢大家的帮助和贴子，我正为此努力.

Thanks everybody for there help and posts I was pulling my hair out on this one.

再次感谢

推荐答案

您可以执行以下操作:

extension String {
    var numberOfVowels: Int {
        let vowels = "aeiou"
        let vowelsSet = NSCharacterSet(charactersInString: vowels)
        let strippedComponents = lowercaseString.componentsSeparatedByCharactersInSet(vowelsSet)
        let stripped = strippedComponents.joinWithSeparator("")
        return characters.count - stripped.characters.count
    }
}

"Hello".numberOfVowels

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