错误传递对VHDL中的函数的类型访问 [英] Error passing type access to function in VHDL

问题描述

我在VHDL中有一条包含指针(access)的记录. 我需要创建一个函数来接收该记录作为参数，并从其数据写入文件中.

I have a record in VHDL that contains a pointer (access). I need to create a function that receives this record as parameter and from its data write in a file.

但是用MODELSIM模拟时，出现以下错误:

But simulating with MODELSIM I get the following error:

**错误:(vcom-1462)非法声明了类型为x_file_format(类型为或包含访问类型)的常量"xxx".

**Error: (vcom-1462) Illegal declaration of constant "xxx" of type x_file_format (type is or contains access type).

如何将指针作为参数传递给函数?

How can I pass a pointer as parameter to a function?

推荐答案

功能参数只能是常量(或信号或文件)输入.访问类型必须是变量.因此，您必须编写一个过程来完成该过程，并将访问类型作为变量传入.

Function parameters can only be constant (or signal or file) inputs. Access types must be variables. Therefore you must write a procedure to do it, with the access type passed in as a variable.

Procedure proc ( variable ptr : someAccessType ) is

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