Python 3如何使用正则表达式在两点之间获取字符串? [英] Python 3 How to get string between two points using regex?

问题描述

如何使用regex或Python 3中的任何其他库在两点之间获取字符串?

How to get the string between two points using regex or any other library in Python 3?

例如: Blah blah ABC要检索的字符串XYZ Blah Blah

For eg: Blah blah ABC the string to be retrieved XYZ Blah Blah

ABC和XYZ是表示我必须检索的字符串的开始和结束的变量.

ABC and XYZ are variables which denote the start and end of the string which I have to retrieve.

推荐答案

使用ABC和XYZ作为具有后向和前向断言的锚点:

Use ABC and XYZ as anchors with look-behind and look-ahead assertions:

(?<=ABC).*?(?=XYZ)

(?<=...)后视断言仅在文本中以ABC开头的位置匹配.同样，(?=XYZ)在XYZ后面的位置匹配.它们共同形成了两个锚点，这些锚点限制了.*表达式，该表达式可以匹配任何内容.

The (?<=...) look-behind assertion only matches at the location in the text that was preceded by ABC. Similarly, (?=XYZ) matches at the location that is followed by XYZ. Together they form two anchors that limit the .* expression, which matches anything.

您可以使用re.findall()找到所有此类锚定文本:

You can find all such anchored pieces of text with re.findall():

for matchedtext in re.findall(r'(?<=ABC).*?(?=XYZ)', inputtext):

如果ABC和XYZ是变量，则要在它们上使用re.escape()(以防止将其任何内容解释为正则表达式语法)并进行插值:

If ABC and XYZ are variable, you want to use re.escape() (to prevent any of their content from being interpreted as regular expression syntax) on them and interpolate:

re.match(r'(?<={}).*?(?={})'.format(abc, xyz), inputtext)

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