使用dplyr，如何通过管道或链式连接到plot()? [英] Using dplyr, how to pipe or chain to plot()?

问题描述

我是dplyr()软件包的新手，正在尝试将其用于可视化任务.我可以将数据通过管道传输到 ggplot()，但不能通过 plot()来完成.我遇到了这篇文章和答案包括评论中的那一项，对我不起作用.

I am new to dplyr() package and trying to use it for my visualization assignment. I am able to pipe my data to ggplot() but unable to do that with plot(). I came across this post and the answers including the one in comments, didn't work for me.

代码1:

emission <- mynei %>%
    select(Emissions, year) %>%
    group_by(year) %>%
    summarise (total=sum(Emissions))

emission %>%
    plot(year, total,.)

我收到以下错误:

Error in plot(year, total, emission) : object 'year' not found

代码2:

mynei %>%
    select(Emissions, year) %>%
    group_by(year) %>%
    summarise (total=sum(Emissions))%>%
    plot(year, total, .)

这也不起作用，并返回了相同的错误.

This didn't work either and returned the same error.

有趣的是，我提到的帖子中的解决方案适用于同一数据集，但不适用于我自己的数据.但是，我可以使用 emission $ year 和 emission $ total 创建图.

Interestingly, the solution from the post I mentioned works for the same dataset but doesn't work out for my own data. However, I am able to create the plot using emission$year and emission$total.

我想念什么吗?

推荐答案

plot.default不采用数据参数，因此最好的选择是通过管道传输到with:

plot.default doesn't take a data argument, so your best bet is to pipe to with:

mynei %>%
    select(Emissions, year) %>%
    group_by(year) %>%
    summarise (total=sum(Emissions))%>%
    with(plot(year, total))

如果有人错过了@aosmith对这个问题的评论，plot.formula 确实有一个数据参数，但是当然formula是第一个参数，因此我们需要使用.将数据放在正确的位置.所以另一种选择是

In case anyone missed @aosmith's comment on the question, plot.formula does have a data argument, but of course the formula is the first argument so we need to use the . to put the data in the right place. So another option is

... %>%
  plot(total ~ year, data = .)

当然，ggplot将data作为第一个参数，因此要使用ggplot做:

Of course, ggplot takes data as the first argument, so to use ggplot do:

... %>%
  ggplot(aes(x = year, y = total)) + geom_point()

lattice::xyplot就像plot.formula:有一个数据参数，但不是第一个，所以:

lattice::xyplot is likeplot.formula: there is a data argument, but it's not first, so:

... %>% 
  xyplot(total ~ year, data = .)

只需查看文档，并确保如果data不是第一个参数，则使用..如果根本没有data参数，那么使用with是一个很好的解决方法.

Just look at the documentation and make sure you use a . if data isn't the first argument. If there's no data argument at all, using with is a good work-around.

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