蟒蛇:通过海报发布stringIO内的数据? [英] python : post data within stringIO through poster?

问题描述

params = {'file': open("test.txt", "rb"), 'name': 'upload test'}
datagen, headers = poster.encode.multipart_encode(params)
request = urllib2.Request(upload_url, datagen, headers)
result = urllib2.urlopen(request)

我使用海报库来发布HTTP.它运作良好.我对此感到满意.

I use poster library to POST for HTTP. It works well. I'm satisfied with that.

但是我想尝试一下.如您在上面看到的，要发送文件数据，我必须打开一个文件.但是，有没有办法不制作一个真实的文件呢?我们可以使用STREAM(如StringIO)来处理文件之类的数据，对吗?但是，我对poster并不了解.因此，我想知道将STREAM与poster一起使用的方法.

But I want to try something. As you see above, to send file data, I have to OPEN a file. But is there any way not to make a real file to do that? We can use a STREAM, like StringIO, to deal with data like a file, right? But, I don't know about poster deeply. So, I want to know the method to use a STREAM with poster.

实际上，我尝试过发布图像数据.我在下面写了这个

Actually, I tried to POST image data. I wrote this below

from PyQt4 import QtCore, QtGui
from poster.encode import multipart_encode
from poster.streaminghttp import register_openers
import urllib2, os

register_openers()
app = QtGui.QApplication(sys.argv)
pixmap = QtGui.QPixmap("c:/test_img.png")
byte_array = QtCore.QByteArray()
buffer = QtCore.QBuffer(byte_array)
buffer.open(QtCore.QIODevice.WriteOnly)
pixmap.save(buffer, "PNG")
from cStringIO import StringIO
datagen, headers = multipart_encode({"image": StringIO(str(byte_array.toBase64()))})
request = urllib2.Request(upload_url, datagen, headers)
_rnt = urllib2.urlopen(request)

但是，我收到此错误:

Traceback (most recent call last):
  File "<pyshell#25>", line 1, in <module>
    _rnt = urllib2.urlopen(request)
  File "C:\Python26\lib\urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "C:\Python26\lib\urllib2.py", line 397, in open
    response = meth(req, response)
  File "C:\Python26\lib\urllib2.py", line 510, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python26\lib\urllib2.py", line 435, in error
    return self._call_chain(*args)
  File "C:\Python26\lib\urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "C:\Python26\lib\urllib2.py", line 518, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 500: Internal Server Error

推荐答案

file参数是您传递文件对象的位置.那么，如果您改为传递类似文件的对象会发生什么呢?

The file param is where you pass the file object. So, what happens if you pass a file-like object instead?

>>> params = {'file': cStringIO.StringIO('upload test data'), 'name': 'upload test'}
>>> datagen, headers = poster.encode.multipart_encode(params)
>>> headers
{'Content-Length': '317', 'Content-Type': 'multipart/form-data; boundary=0c56082b1e134424a918b2b083391467'}

看起来很有效.

文档说什么?

What does the documentation say?

值可以是字符串参数值，也可以是用作参数值的类似文件的对象.类似于文件的对象必须支持.read()和.fileno()或同时支持.seek()和.tell().

Values are either strings parameter values, or file-like objects to use as the parameter value. The file-like objects must support .read() and either .fileno() or both .seek() and .tell().

因此，可以使用StringIO对象，因为它们支持seek()和tell().

So, you can use StringIO objects because they support seek() and tell().

但是您不必这样做.您应该能够只使用原始字符串.让我们尝试一下，看看:

But you don't have to. You should be able to just use the raw string. Let's try it and see:

>>> params = {'file': 'upload test data', 'name': 'upload test'}
>>> datagen, headers = poster.encode.multipart_encode(params)
>>> headers
{'Content-Length': '317', 'Content-Type': 'multipart/form-data; boundary=0c56082b1e134424a918b2b083391467'}

看看，文档是正确的.

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