正则表达式，用于用连字符替换字符串中的所有特殊字符和空格 [英] Regex for replacing all special characters and spaces in a string with hyphens

问题描述

我有一个字符串，需要替换所有特殊字符〜！@#$％^& *()_ + =`{} [] |:;'<>，./?"和带连字符的空格.连续多个特殊字符应产生一个连字符.

I have a string in which I need to replace all the special characters "~!@#$%^&*()_+=`{}[]|:;'<>,./?" and spaces with hyphens. Multiple special characters in a row should result in a single hyphen.

var mystring="Need !@#$%^\" to /replace  this*(){}{}|\><? with_new string ";
// desired output: "Need-to-replace-this-with-new-string"

目前，我正在使用以下一系列replace()调用:

At present, I'm using this series of replace() calls:

return mystring.replace(/[^a-z0-9\s]/gi, '').replace(/[_\s]/g, '-').replace(/\//g, "-");

但是它正在输出:

Need----------to/replace-this--------with-new-string;

它将为字符串中的每个特殊字符添加连字符(除正斜杠之外).

where it's adding a hyphen for every special character in the string except for the forward slash.

推荐答案

我建议:

var inputString = "~!@#$%^&*()_+=`{}[]|\:;'<>,./?Some actual text to keep, maybe...",
    outputString = inputString.replace(/([~!@#$%^&*()_+=`{}\[\]\|\\:;'<>,.\/? ])+/g, '-').replace(/^(-)+|(-)+$/g,'');
console.log(outputString);

JS小提琴演示.

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