需要帮助在bash脚本中使用grep/egrep匹配问题 [英] Need help matching a mattern using grep/egrep in bash scripting

问题描述

我正在尝试匹配给定字符串的所有字符，但这些字符应按照bash脚本给出的顺序进行匹配.

I am trying to match all characters of given string but those characters should match in the order as given to the bash script.

while [[ $# -gt 0 ]]; do
  case $1 in
       -i)
    arg=$2
    egrep "*[$arg]*" words.txt 
    shift ;;
  esac
  shift
done

$ sh match_the_pattern.sh -i aei words.txt

应返回类似

abstentious
adventitious
sacrilegiousness

如果您注意到，首先匹配a，然后匹配e，然后匹配i，它们都是按顺序排列的.另外，整个单词都经过匹配和过滤.

If you notice, first a is matched then e and then i, all of them are in order. Plus, the whole word is matched and filtered.

推荐答案

更改此内容:

arg=$2
egrep "*[$arg]*" words.txt

对此:

arg=$(sed 's/./.*[&]/g' <<< "$2")
grep "$arg" words.txt

如果这还不是您所需要的，那么请编辑您的问题以阐明您的要求，并提供更真实的示例输入/输出.

If that's not all you need then edit your question to clarify your requirements and provide more truly representative sample input/output.

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