在特殊字符前匹配字符串 [英] Match strings before special character

问题描述

我正在尝试匹配两列中的字符串，并在：之前返回不匹配项。如果x2x，y67y不返回，因为x仍然是x，y仍然是y。

I am trying to match strings in two columns and return mismatches before ":". It should not return if x2x, y67y, as x remains x and y remains as y.

我不想匹配：decimal。如果x2y都在两列中，则表示匹配（无论特殊字符后的小数点不匹配）
INPUT：

I don't want to match the ":decimal". If x2y is in both columns then its a match (irrespective of the mismatch in the decimal after special character) INPUT:

input <- structure(list(x = structure(c(1L, 2L, 3L, 3L), .Label = c("A", 
"B", "C"), class = "factor"), y = structure(c(2L, 3L, 1L, 4L), .Label = c("A", 
"B", "C", "D"), class = "factor"), x_val = c("x2x:0.12345,y67h:0.06732,d7j:0.032647", 
"x2y:0.26345,y67y:0.28320,d7r:0.043647", "x2y:0.23435,y67y:0.28310,d7r:0.043547", 
"x2y:0.23435,y67y:0.28330,d7r:0.043247"), y_val = c("x2y:0.33134,y67y:0.3131,d7r:0.23443", 
"x2y:0.34311,y67y:0.14142,d7r:0.31431", "x2x:0.34314,y67h:0.14141,d7j:0.453145", 
"x67b:0.31411,g72v:0.3134,b8c:0.89234")), row.names = c(NA, -4L
), class = "data.frame")

输出：

output <- structure(list(x = structure(c(1L, 2L, 3L, 3L), .Label = c("A", 
"B", "C"), class = "factor"), y = structure(c(2L, 3L, 1L, 4L), .Label = c("A", 
"B", "C", "D"), class = "factor"), x_val = c("x2x:0.12345,y67h:0.06732,d7j:0.032647", 
"x2y:0.26345,y67y:0.28320,d7r:0.043647", "x2y:0.23435,y67y:0.28310,d7r:0.043547", 
"x2y:0.23435,y67y:0.28330,d7r:0.043247"), y_val = c("x2y:0.33134,y67y:0.3131,d7r:0.23443", 
"x2y:0.34311,y67y:0.14142,d7r:0.31431", "x2x:0.34314,y67h:0.14141,d7j:0.453145", 
"x67b:0.31411,g72v:0.3134,b8c:0.89234"), diff_x = c("y67h:0.06732,d7j:0.03264", 
NA, "x2y:0.23435,d7r:0.043547", "x2y:0.23435,y67y:0.28330,d7r:0.043247"
), diff_y = c("x2y:0.33134,d7r:0.23443", NA, "y67h:0.14141,d7j:0.453145", 
"x67b:0.31411,g72v:0.3134,b8c:0.89234")), row.names = c(NA, -4L
), class = "data.frame")

我只想匹配到：字符时遇到问题。以下代码是从该问题中获取的： https://stackoverflow.com/a/55285959/5150629 。

I run into problem when I just want to match till ":" character. The following code is taken from this question: https://stackoverflow.com/a/55285959/5150629.

library(dplyr)
library(purrr)

I %>% mutate(diff_x = map2_chr(strsplit(x_val, split = ", "), 
                               strsplit(y_val, split = ", "), 
                               ~paste(grep('([a-z])(?>\\d+)(?!\\1)', setdiff(.x, .y), 
                                           value = TRUE, perl = TRUE), 
                                           collapse = ", ")) %>%
               replace(. == "", NA), 
             diff_y = map2_chr(strsplit(x_val, split = ", "), 
                               strsplit(y_val, split = ", "), 
                               ~paste(grep('([a-z])(?>\\d+)(?!\\1)', setdiff(.y, .x), 
                                           value = TRUE, perl = TRUE),
                                           collapse = ", ")) %>%
               replace(. == "", NA))

有人可以帮忙吗？

推荐答案

我在 https://stackoverflow.com/a/中修改了答案55285959/5150629 适合以下问题：

library(dplyr)
library(purrr)

df %>% 
  mutate(
    diff_x = map2_chr(
      strsplit(x_val, split = ","), 
      strsplit(y_val, split = ","), 
      ~ {
        setdiff(sub(":.+$", "", .x), sub(":.+$", "", .y)) %>%
          grep('([a-z])(?>\\d+)(?!\\1)', ., value = TRUE, perl = TRUE) %>%
          sapply(grep, .x, value = TRUE) %>%
          paste(collapse = ", ") %>%
          replace(. == "", NA)
      }
    ),  
    diff_y = map2_chr(
      strsplit(x_val, split = ","), 
      strsplit(y_val, split = ","), 
      ~ {
        setdiff(sub(":.+$", "", .y), sub(":.+$", "", .x)) %>%
          grep('([a-z])(?>\\d+)(?!\\1)', ., value = TRUE, perl = TRUE) %>%
          sapply(grep, .y, value = TRUE) %>%
          paste(collapse = ", ") %>%
          replace(. == "", NA)
      }
    )
  )

输出：

  x y                                 x_val                                 y_val                     diff_x
1 A B x2x:0.12345,y67h:0.06732,d7j:0.032647   x2y:0.33134,y67y:0.3131,d7r:0.23443 y67h:0.06732, d7j:0.032647
2 B C x2y:0.26345,y67y:0.28320,d7r:0.043647  x2y:0.34311,y67y:0.14142,d7r:0.31431                       <NA>
3 C A x2y:0.23435,y67y:0.28310,d7r:0.043547 x2x:0.34314,y67h:0.14141,d7j:0.453145  x2y:0.23435, d7r:0.043547
4 C D x2y:0.23435,y67y:0.28330,d7r:0.043247  x67b:0.31411,g72v:0.3134,b8c:0.89234  x2y:0.23435, d7r:0.043247
                                  diff_y
1               x2y:0.33134, d7r:0.23443
2                                   <NA>
3             y67h:0.14141, d7j:0.453145
4 x67b:0.31411, g72v:0.3134, b8c:0.89234

注意：

1. 因为我们只想比较第一个字符串格式 x1y：000000 的一部分，我添加了 sub（：。+ $，，.x） map2_chr 输入参数$ c>首先剥去：000000 部分。

1. Since we are only interested in comparing the first part of the string format x1y:000000, I added a sub(":.+$", "", .x) for each map2_chr input argument to strip out the :000000 part first.

setdiff 和以下 grep 步骤可以正常工作以返回不匹配项，并排除格式为 x1x 的字符串。

setdiff and the following grep steps work as expected to return the mismatches and exclude strings with the form x1x.

sapply（grep，.x，value = TRUE） > grep 获取不匹配的向量，并搜索其对应的原始字符串（格式为 x1y：000000 ）。

sapply(grep, .x, value = TRUE) after the first grep takes the vector of mismatches, and searches for their corresponding original strings (in x1y:000000 form).

粘贴将不匹配的向量折叠成一个逗号分隔的列表。

paste collapses the vector of mismatches into a single comma separated list.

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